Answer:
B. binding of glucose causes a conformational change so that the transporter is never open on both sides of the membrane
Plant cell have cell wall while animal cell do not.
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Answer:
d. ATP; Fructose-2,6-bisphosphate
Explanation:
Phosphofructokinase-1 is the enzyme that catalyzes the formation of fructose-1,6-bisphosphate from fructose-6-phosphate and ATP. The phosphofructokinase step is the first rate-limiting step of glycolysis.
Phosphofructokinase-1 activity is allosterically regulated. Its activity is increased whenever the cell's ATP supply is depleted or when its breakdown products, ADP and AMP accuulates in he cell. However, it is inhibited when the cell is amply supplied with ATP.
The activity of phosphofructokinase-1 is restored by fructose-2,6-bisphosphate, its most potent activator.
From the given options:
a. AMP :::: citrate is wrong because AMP increases the activity of phosphofructokinase-1 and citrate is not its activator but an inhibitor
b. AMP :::: Fru-2,6-P2 is wrong because AMP increases its activity same as fructose-2,6-bisphosphate
c. ATP :::: citrate is wrong because both citrate and ATP are inhibitors
d. ATP :::: Fru-2,6-P2 is correct as explained above
e. All of these is wrong because of the other wrong options above.