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3 years ago

What is the value of 8 in 293,581

1 answer:

7 0

Is it a decimal ? or a whole number ?

if it is a decimal , the value is 8 tenths

if it’s a whole number , the value is 8 tens

hope this helped

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What is the equation for this line

pogonyaev

The equation of the line is $y=\frac{-1}{5} x-\frac{21}{5}$ .

Solution:

The points on the line are (–6, –3) and (4, –5).

$x_{1}=-6, y_{1}=-3, x_{2}=4, y_{2}=-5$

Slope of the line:

$$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$$m=\frac{-5-(-3)}{4-(-6)}$

$$m=\frac{-5+3}{4+6}$

$$m=\frac{-2}{10}$

$$m=\frac{-1}{5}$

Point-slope formula:

$y-y_{1}=m\left(x-x_{1}\right)$

$$y-(-3)=\frac{-1}{5}(x-(-6))$

$$y+3=\frac{-1}{5}(x+6)$

$$y+3=\frac{-1}{5} x-\frac{6}{5}$

Subtract 3 from both sides of the equation.

$$y=\frac{-1}{5} x-\frac{21}{5}$

The equation of the line is $y=\frac{-1}{5} x-\frac{21}{5}$ .

6 0

3 years ago

Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

I will try to give as many details as possible.

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Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! （＊＾Ｕ＾）人（≧Ｖ≦＊）/

$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

4 0

3 years ago

What is each expression written using each base only once? (-4)^-6*(-4)^7

andreyandreev [35.5K]

(-4)^-6*(-4)^7 = (-4)^1 = -4

answer a. -4

6 0

3 years ago

Read 2 more answers

Convert 800 milliliters to liters. A. 8 L B. 80 L C. 0.8 L D. 0.08 L

ANTONII [103]

The answer is c. 0.8 L

7 0

3 years ago

Simplify each expression 8x+13-3x+9

igor_vitrenko [27]

Answer:

5x+22

Step-by-step explanation:

8x-3x = 5x

13+9 = 22

Remember sign stays with the number

6 0

3 years ago