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3 years ago

Which of the following statements are true?

Mathematics

2 answers:

scoray [572]3 years ago

6 0

Answer:

All diagonal matrices are square matrices.

The size of any square matrix is m x m, where m is a positive integer.

jolli1 [7]3 years ago

4 0

Answer:

B. All diagonal matrices are square matrices.

C. The size of any square matrix is m x m, where m is a positive integer.

Step-by-step explanation:

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Find r if 0=pi/6 rad sector 64m^2

kap26 [50]

Given:

Area of a sector = 64 m²

The central angle is $\theta=\dfrac{\pi}{6}$ .

To find:

The radius or the value of r.

Solution:

Area of a sector is:

$A=\dfrac{1}{2}r^2\theta$

Where, r is the radius of the circle and $\theta$ is the central angle of the sector in radian.

Putting $A=64,\theta=\dfrac{\pi}{6}$ , we get

$64=\dfrac{1}{2}r^2\times \dfrac{\pi}{6}$

$64=\dfrac{\pi}{12}r^2$

$64\times \dfrac{12}{\pi}=r^2$

$\dfrac{768}{\pi}=r^2$

Taking square root on both sides, we get

$\sqrt{\dfrac{768}{\pi}}=r$

$16\sqrt{\dfrac{3}{\pi}}=r$

Therefore, the value of r is $16\sqrt{\dfrac{3}{\pi}}$ m.

6 0

2 years ago

What is the equation of a horizontal line passing through the point (2, 10)?<br> (1 Point)

Citrus2011 [14]

Answer:

y=5x+10

Step-by-step explanation:

8 0

2 years ago

Which of the following is equal to the expression (8x)^-2/3 (27x)¯1/3

LiRa [457]

The equivalent expression of (8x)^-2/3 * (27x)^-1/3 is 1/12x

<h3>How to evaluate the expression?</h3>

The expression is given as:

(8x)^-2/3 * (27x)^-1/3

Evaluate the exponent 8^-2/3

(8x)^-2/3 * (27x)^-1/3 = 1/4(x)^-2/3 * (27x)^-1/3

Evaluate the exponent (27x)^-1/3

(8x)^-2/3 * (27x)^-1/3 = 1/4(x)^-2/3 * 1/3(x)^-1/3

Multiply 1/4 and 1/3

(8x)^-2/3 * (27x)^-1/3 = 1/12(x)^-2/3 * (x)^-1/3

Evaluate the exponent

(8x)^-2/3 * (27x)^-1/3 = 1/12(x)^(-2/3 -1/3)

This gives

(8x)^-2/3 * (27x)^-1/3 = 1/12(x)^(-1)

So, we have

(8x)^-2/3 * (27x)^-1/3 = 1/12x

Hence, the equivalent expression of (8x)^-2/3 * (27x)^-1/3 is 1/12x

Read more about equivalent expression at

brainly.com/question/2972832

#SPJ1

3 0

4 months ago

What times what equals 225?

defon

I got 5 times 45 because I multiplied by 5 to get my answer.

4 0

3 years ago

A garden hose having an internal diameter of 0.740 in. ( 1.8796 cm ) is connected to a lawn sprinkler that consists merely of an

lara31 [8.8K]

Answer:

It will leave the sprinkler at speed of $v_2=613.87m/sec$

Step-by-step explanation:

We have given internal diameter of the garden hose $d_1=0.740in=1.8796cm$

So radius $r_1=\frac{d_1}{2}=\frac{1.8796}{2}=0.9398cm$

So area $A_1=\pi r_1^2=3.14\times 0.9398^2=2.7733cm^2$

Water in the hose has a speed of 4 ft/sec

So $v_1=4ft/sec=121.92cm/sec(As\ 1ft/sec\ =30.48cm/sec)$

Number of holes n = 36

Diameter of each hole $d_2=0.1397cm$

So radius $r_2=0.0698cm$

So area $A_2=\pi r^2=3.14\times 0.0698^2=0.0153cm^2$

From continuity equation

$A_1v_1=nA_2v_2$

$2.7733\times 121.92=36\times 0.0153\times v_2$

$v_2=613.87m/sec$

7 0

2 years ago