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Finger [1]
3 years ago
13

I will give brainlist to the most helpful answer to my question

Mathematics
1 answer:
sdas [7]3 years ago
7 0

Answer:

See below

Step-by-step explanation:

Both horses travel 0 miles in 0 minutes. We can see this on the graph where both lines start at the 0 in the bottom left corner. For the purpose of writing the equations this also shows us that the y-intercept is 0. In a slope-intercept equation, y=mx+b, that number is the b. b is zero in both equations, so we don't need to write anything for that.

For horse A, we can see on the graph that at 4 minutes, horse A has traveled 1 mile. Also, confirming this rate, at 8 minutes, it went 2 miles. This will help us find the rate. The rate will be the number we fill in for the m in the y=mx+b equation. Horse A goes 1mile every 4 minutes. That is a rate of 1/4 miles per minute. So Horse A's equation will be

y = (1/4)x You can make it more *intuitive* possibly by using m for miles and t for time instead, like this:

m = (1/4)t

Horse B is a little bit faster, and you can see this bc the line is a little bit steeper. It goes 2 miles in 5 minutes (confirm you can see it goes 4 miles in 10 minutes)

So Horse B's equation is

y = (2/5)x

or miles = (2/5)time

Mathematically, the equations are the same whether you use x,y or m,t

If Horse A runs for 12 minutes then it will run

miles = (1/4)minutes

miles = (1/4)(12)

miles = 3

If Horse B runs for 12 minutes, then it will run

miles = (2/5)minutes

miles = (2/5)12

miles = 4.8

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depending on if you want fractions or decimals

explanation:
equation for midpoint... (avg x, avg y)
x-coordinate: (6+9)/2 = 15/2 = 7.5
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3 years ago
In scientific notation,the distance is m×10n where is ..and n is..
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Find the area of a circle with a diameter of 16.Answer as a decimal
Vlad1618 [11]

Answer:

201.06

Step-by-step explanation:

This is because the formula of the area of a circle is A=(pi)(r) squared

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6 0
3 years ago
1. A MAP SCALE READS 1CM:5KM. IF A DISTANCE ON THE MAP MEASURES 7CM, THE ACTUAL DISTANCE WILL BE?. 2. A SCHOOL DINING HALL IS 35
Agata [3.3K]

Answer:

1. 35 km

2. 1 cm to 5m

3. 6 cm

4. 42^\circ

5. 16.73 m

Step-by-step explanation:

Solution 1.

Reading of map scale = 1cm:5km

i.e. 1 cm is equivalent to 5 km

Measurement of map  = 7 cm

Actual distance = Measurement of map \times 5

Actual distance = 7 \times 5 = <em>35 km</em>

-------------------

Solution 2.

Length of dining hall = 35 m

Measurement of map = 7 cm

Scale = Measurement of map : Length of dining hall (i.e. ratio)

Scale = 7 cm :35 m = <em>1 cm : 5 m</em>

-------------------

Solution 3.

Length of building = 30 m

Scale = 1 cm to 5m

5 m is equivalent to 1 cm on scale

1 m is equivalent to \frac{1}{5} cm on scale

30m is equivalent to \frac{1}{5} \times 30 = <em>6 cm</em> on scale

-------------------

Solution 4.

Angle of elevation of A from B = 42^\circ

Angle of depression of B from A = ?

Please refer to the image attached, we can clearly observe that both the angles (i.e. angle of elevation from A to B and angle of depression from B to A )will be equal.

Angle of depression of B from A = 42^\circ

-------------------

Solution 5.

Given that:

String length, or hypotenuse of triangle BC= 25 m

Angle of string with horizontal, \angle B  = 42^\circ

Please refer to the attached image for the clear understanding of the situation.

To find:

Height, AC = ?

We can use trigonometric identity:

sin\theta = \dfrac{Perpendicular}{Hypotenuse}

OR

sinB = \dfrac{AC}{BC}\\\Rightarrow sin42^\circ = \dfrac{AC}{25}\\\Rightarrow AC = 25 \times 0.67\\\Rightarrow AC = 16.73 m

============

So, the answers are:

1. 35 km

2. 1 cm to 5m

3. 6 cm

4. 42^\circ

5. 16.73 m

7 0
3 years ago
3. The Human Resources department of a large corporation wants to estimate the mean number
VARVARA [1.3K]

Answer:

The 90% confidence level margin of error for this sample mean is 0.42

Step-by-step explanation:

The Human Resources department conduct a random sample of 30  employees

n = 30

Standard deviation = \sigma = 1.4

z = 1.645

Formula of 90% confidence level margin of error for this sample mean=Z \times \frac{\sigma}{\sqrt{n}}

So, margin of error for this sample mean=1.645 \times \frac{1.4}{\sqrt{30}}

So, margin of error for this sample mean=0.42

Hence the 90% confidence level margin of error for this sample mean is 0.42

7 0
4 years ago
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