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Finger [1]
2 years ago
13

I will give brainlist to the most helpful answer to my question

Mathematics
1 answer:
sdas [7]2 years ago
7 0

Answer:

See below

Step-by-step explanation:

Both horses travel 0 miles in 0 minutes. We can see this on the graph where both lines start at the 0 in the bottom left corner. For the purpose of writing the equations this also shows us that the y-intercept is 0. In a slope-intercept equation, y=mx+b, that number is the b. b is zero in both equations, so we don't need to write anything for that.

For horse A, we can see on the graph that at 4 minutes, horse A has traveled 1 mile. Also, confirming this rate, at 8 minutes, it went 2 miles. This will help us find the rate. The rate will be the number we fill in for the m in the y=mx+b equation. Horse A goes 1mile every 4 minutes. That is a rate of 1/4 miles per minute. So Horse A's equation will be

y = (1/4)x You can make it more *intuitive* possibly by using m for miles and t for time instead, like this:

m = (1/4)t

Horse B is a little bit faster, and you can see this bc the line is a little bit steeper. It goes 2 miles in 5 minutes (confirm you can see it goes 4 miles in 10 minutes)

So Horse B's equation is

y = (2/5)x

or miles = (2/5)time

Mathematically, the equations are the same whether you use x,y or m,t

If Horse A runs for 12 minutes then it will run

miles = (1/4)minutes

miles = (1/4)(12)

miles = 3

If Horse B runs for 12 minutes, then it will run

miles = (2/5)minutes

miles = (2/5)12

miles = 4.8

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Identify the variation as a direct, inverse, joint, or combined.<br> xy/z=c
Korvikt [17]

The given equation is a combined variation.

We have been given an equation is

\frac{xy}{z}

This is an equation in which we have three variables and one constant.

This can not be the case of direct or inverse variation because in direct or inverse variation we have only two variables. Whereas, here we have three variables.

So, Direct and inverse options are discarded.

So, either It can be joint or combined

In joint variation both the variables are directly proportional

Hence, given equation is not joint because if we rewrite the equation we will get y = \frac{cz}{x} both the variables are not directly proportional.

In combined, one variable is directly proportional and the other one is inversely proportional.

From y = \frac{cz}{x}  we can see that z is directly proportional and x is inversely proportional.

Hence the answer is, the given equation is combined variation.

To learn more about variations click here brainly.com/question/2375770

#SPJ9

3 0
1 year ago
Am I correct?? I did not count the last square unit at the vertices of each corner.
mariarad [96]
The answer would actually be a 110 units because the bottom left corner had 20 units and the bigger square had 90.
3 0
3 years ago
Which scenario does not represent exponential growth?
storchak [24]

Answer:

I believe the correct answer is - The value of a bank account with quarterly compounded interest after 6 years.

I'm not sure if this is 100% correct but hope it helps.

4 0
2 years ago
An expression is shown below. Which expression is equivalent to the expression shown?
olya-2409 [2.1K]

Answer:

where's the options

Step-by-step explanation:

i think you made a mistake

3 0
2 years ago
Read 2 more answers
The heat index I is a measure of how hot it feels when the relative humidity is H (as a percentage) and the actual air temperatu
PSYCHO15rus [73]

Answer:

a) I(95,50) = 73.19 degrees

b) I_{T}(95,50) = -7.73

Step-by-step explanation:

An approximate formula for the heat index that is valid for (T ,H) near (90, 40) is:

I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}

a) Calculate I at (T ,H) = (95, 50).

I(95,50) = 45.33 + 0.6845*(95) + 5.758*(50) - 0.00365*(95)^{2} - 0.1565*95*50 + 0.001*50*95^{2} = 73.19 degrees

(b) Which partial derivative tells us the increase in I per degree increase in T when (T ,H) = (95, 50)? Calculate this partial derivative.

This is the partial derivative of I in function of T, that is I_{T}(T,H). So

I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}

I_{T}(T,H) = 0.6845 - 2*0.00365T - 0.1565H + 2*0.001H

I_{T}(95,50) = 0.6845 - 2*0.00365*(95) - 0.1565*(50) + 2*0.001(50) = -7.73

8 0
3 years ago
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