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3 years ago

15

Bob will run at least 28 miles this week. So far, he has run 18 miles. What are the possible numbers of additional miles he will

run?

1 answer:

Yuki888 [10]3 years ago

5 0

Answer:

10 miles (please brainliest me if can‘

Step-by-step explanation:

28-18 is 10

hope this helps :)

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3 years ago

If a survey of a movie shows that 50% of all people who like the movie, enjoyed the official movie soundtrack too. If a total of

Murljashka [212]

Answer:

For the first question the sample size is n= 3850

$ME= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$\hat p \pm ME$

And replacing we got:

$0.5- 0.016 = 0.484$

$0.5+ 0.016 = 0.516$

We are confident at 95% that the true proportion of all people who like the movie is between 0.484 and 0.516.

Step-by-step explanation:

We have the following info given:

$\hat p = 0.5$ represent the estimated proportion of all people who like the movie

$n = 3850$ represent the sample size selected

For the first question the sample size is n= 3850

For the second part they gives to us the margin of error:

$ME = 0.016$

We know that the confidence interval for a population proportion $p$ of interest is given by:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

And the margin of error is given by:

$ME= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

So then the confidence interval can be found with this formula:

$\hat p \pm ME$

And replacing we got:

$0.5- 0.016 = 0.484$

$0.5+ 0.016 = 0.516$

We are confident at 95% that the true proportion of all people who like the movie is between 0.484 and 0.516.

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3 years ago