What is 2015722184 multiplied by 142748261654 i cant find this on calculator for some reason

If m∠XWY = 20°, m∠XWZ = 40°, and XY = 16, what is the value of YZ?

Jobisdone [24]

YZ = 16. The triangles are congruent. This would be AAS so YZ = 16 because of CPCTC.

7 0

2 years ago

Convert 5 2/7 to 7ths (there’s the image if you’re confused.)

MrMuchimi

Answer:

37/7

Step-by-step explanation:

to get 37-

7x5+2, then you get 37! you then put that over the denpminator, if you're confused look at the pic

7 0

2 years ago

Evaluate 4x exponent 2+ 2x-1 for x=9

olasank [31]

The value of given expression is 341

Solution:

Given that we have to find the value of given expression

Given expression is:

$4x^2 + 2x - 1$

Given value is x = 9

Substitute x = 9 in given expression

$\rightarrow 4(9)^2+2(9) - 1$

Solve the above expression

$\rightarrow 4 \times (9 \times 9) + 18 -1\\\\\rightarrow 4 \times 81 + 17\\\\\text{Multiply the terms 4 and 81 }\\\\\rightarrow 324 + 17\\\\\text{Add the numbers }\\\\\rightarrow 341$

Thus the value of given expression is 341

8 0

3 years ago

Consider the oriented path which is a straight line segment L running from (0,0) to (16, 16 (a) Calculate the line integral of t

aalyn [17]

This question is missing some parts. Here is the complete question.

Consider the oriented path which is a straight line segment L running from (0,0) to (16,16).

(a) Calculate the line inetrgal of the vector field F = (3x-y)i + xj along line L using the parameterization B(t) = (2t,2t), 0 ≤ t ≤ 8.

Enter an exact answer.

$\int\limits_L {F} .\, dr =$

(b) Consider the line integral of the vector field F = (3x-y)i + xj along L using the parameterization C(t) = $(\frac{t^{2}-256}{48} ,\frac{t^{2}-256}{48} )$ , 16 ≤ t ≤ 32.

The line integral calculated in (a) is ____________ the line integral of the parameterization given in (b).

Answer: (a) $\int\limits_L {F} .\, dr =$ 384

(b) the same as

Step-by-step explanation: Line Integral is the integral of a function along a curve. It has many applications in Engineering and Physics.

It is calculated as the following:

$\int\limits_C {F}. \, dr = \int\limits^a_b {F(r(t)) . r'(t)} \, dt$

in which (.) is the dot product and r(t) is the given line.

In this question:

(a) F = (3x-y)i + xj

r(t) = B(t) = (2t,2t)

interval [0,8] are the limits of the integral

To calculate the line integral, first substitute the values of x and y for 2t and 2t, respectively or

F(B(t)) = 3(2t)-2ti + 2tj

F(B(t)) = 4ti + 2tj

Second, first derivative of B(t):

B'(t) = (2,2)

Then, dot product between F(B(t)) and B'(t):

F(B(t))·B'(t) = 4t(2) + 8t(2)

F(B(t))·B'(t) = 12t

Now, line integral will be:

$\int\limits_C {F}. \, dr = \int\limits^8_0 {12t} \, dt$

$\int\limits_L {F}. \, dr = 6t^{2}$

$\int\limits_L {F.} \, dr = 6(8)^{2} - 0$

$\int\limits_L {F}. \, dr = 384$

Line integral for the conditions in (a) is 384

(b) same function but parameterization is C(t) = $(\frac{t^{2}-256}{48}, \frac{t^{2}-256}{48} )$ :

F(C(t)) = $\frac{t^{2}-256}{16}-\frac{t^{2}-256}{48}i+ \frac{t^{2}-256}{48}j$

F(C(t)) = $\frac{2t^{2}-512}{48}i+ \frac{t^{2}-256}{48} j$

C'(t) = $(\frac{t}{24}, \frac{t}{24} )$

$\int\limits_L {F}. \, dr = \int\limits {(\frac{t}{24})(\frac{2t^{2}-512}{48})+ (\frac{t}{24} )(\frac{t^{2}-256}{48}) } \, dt$

$\int\limits_L {F} .\, dr = \int\limits^a_b {\frac{t^{3}}{384}- \frac{768t}{1152} } \, dt$

$\int\limits_L {F}. \, dr = \frac{t^{4}}{1536} - \frac{768t^{2}}{2304}$

Limits are 16 and 32, so line integral will be:

$\int\limits_L {F} \, dr = 384$

With the same function but different parameterization, line integral is the same.

6 0

3 years ago

Create and solve a linear equation that represents the model, where squares and triangles are shown evenly balanced on a balance

Rina8888 [55]

Let the weight of triangle be x units. You are given that the weight of square is 1 unit.

1) On the left side of the balanced beam you can see 3 triangles and 5 squares. The weight on left side is 3·x+5·1=3x+5 units.

2) On the right side of the balanced beam you can see 2 triangles and 7 squares. The weight on right side is 2·x+7·1=2x+7 units.

3) If the whole system is balanced, then the weights on left and right sides are equal:

3x+5=2x+7.

Solve this equation:

3x-2x=7-5,

x=2 units.

Answer: option A

8 0

2 years ago