Sadly is right. You must have practiced this stuff in middle school
until it was coming out of your ears. Fortunately, you have a chance
to relearn it now. You should do that ... it'll be important in any math
course you ever take.
'm' is the slope of the line on the graph.
The slope is
(the change in 'y' between any two points on the line)
divided by
(the change in 'x' between the same two points).
You can choose any two points on the line, and the slope is always the same.
To make it easy, look at the two points on this graph where the line crosses
the x-axis and the y-axis.
Going between these two points ...
-- the line goes up, from y=0 to y=4. The change in 'y' is 4 .
-- the line goes to the right, from x=-2 to x=0. The change in 'x' is 2 .
'm' = the slope = (4)/(2) = 2 .
The "y-intercept" is the place where the line crosses the y-axis.
On this graph, that's the point where y=4 .
The equation of EVERY straight line on ANY graph is:
Y = (the slope) times 'x' + (the y-intercept) .
So the equation of THIS line on THIS graph is
Y = 2x + 4 .
General Idea:
Domain of a function means the values of x which will give a DEFINED output for the function.
Applying the concept:
Given that the x represent the time in seconds, f(x) represent the height of food packet.
Time cannot be a negative value, so

The height of the food packet cannot be a negative value, so

We need to replace
for f(x) in the above inequality to find the domain.
![-15x^2+6000\geq 0 \; \; [Divide \; by\; -15\; on\; both\; sides]\\ \\ \frac{-15x^2}{-15} +\frac{6000}{-15} \leq \frac{0}{-15} \\ \\ x^2-400\leq 0\;[Factoring\;on\;left\;side]\\ \\ (x+200)(x-200)\leq 0](https://tex.z-dn.net/?f=%20-15x%5E2%2B6000%5Cgeq%200%20%5C%3B%20%5C%3B%20%20%5BDivide%20%5C%3B%20by%5C%3B%20-15%5C%3B%20on%5C%3B%20both%5C%3B%20sides%5D%5C%5C%20%5C%5C%20%5Cfrac%7B-15x%5E2%7D%7B-15%7D%20%2B%5Cfrac%7B6000%7D%7B-15%7D%20%5Cleq%20%5Cfrac%7B0%7D%7B-15%7D%20%5C%5C%20%5C%5C%20x%5E2-400%5Cleq%200%5C%3B%5BFactoring%5C%3Bon%5C%3Bleft%5C%3Bside%5D%5C%5C%20%5C%5C%20%28x%2B200%29%28x-200%29%5Cleq%200%20)
The possible solutions of the above inequality are given by the intervals
. We need to pick test point from each possible solution interval and check whether that test point make the inequality
true. Only the test point from the solution interval [-200, 200] make the inequality true.
The values of x which will make the above inequality TRUE is 
But we already know x should be positive, because time cannot be negative.
Conclusion:
Domain of the given function is 
(- 2, - 3) is a solution to the given system of equations.
Answer: Option D
<u>Step-by-step explanation:</u>
Given equation are not presented in proper format. So, let assume the given system of are as below,
2 x - y = -1
2 x -4 y = 8
Now, subtract the second equation from the first, we get
(2 x - y) -(2 x - 4 y) = -1 -8
3 y = -9
y = -3 (obtained this when divide by 3)
Substituting y = - 3 into the first equation, we get
2 x - (-3) = - 1
2 x = - 1 + 3
x = - 2 (obtained when divide by 2)
Now, the answer is (x, y) = (- 2, - 3)
Yea what the other guy said
Answer:
x1=3 x2=-5
BUT x1=3 is not an answer because it doesnt respects the range on the original ecuation, so x2=-5 is the solution
Step-by-step explanation: