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nikdorinn [45]
3 years ago
13

How do I find the acceleration and if you could just put the equation in your answer. Thanks a lot.

Physics
1 answer:
Dafna1 [17]3 years ago
7 0

You use Newton's second law, which says that the net force acting on a body is equal to the product of the body's mass and the acceleration it undergoes. That is,

\sum\vec F=m\vec a

From the question, it sounds like the given force is the only force acting on the block, which means there is only going to be one direction of movement if the acceleration is constant. This allows us to ignore the vector notation and talk only in terms of magnitudes. The above equation reduces to

F=ma

So in this case,

F=ma\implies a=\dfrac Fm

and numerically, we get

a=\dfrac{40\,\rm N}{12.5\,\rm kg}=3.2\,\dfrac{\rm m}{\mathrm s^2}

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A hard drive disk rotates at 7200 rpm. The disk has a diameter of 5.1 in (13 cm). What is the speed of a point 6.0 cm from the c
ExtremeBDS [4]

Answer:

The speed will be "3.4×10⁴ m/s²".

Explanation:

The given values are:

Angular speed,

w = 7200 rpm

i.e.,

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Speed from the center,

r = 6.0 cm

As we know,

⇒  Linear speed, v=wr

On putting the estimated values, we get

                               =753.6\times 0.06

                               =45.216 \ m

Now,

Acceleration on disk will be:

⇒  a=\frac{v^2}{r}

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A tank of water is in the shape of a cone (assume the ""point"" of the cone is pointing downwards) and is leaking water at a rat
Inessa05 [86]

Answer:

a) dh/dt = -44.56*10⁻⁴ cm/s

b) dr/dt = -17.82*10⁻⁴ cm/s

Explanation:

Given:

Q = dV/dt = -35 cm³/s

R = 1.00 m

H = 2.50 m

if h = 125 cm

a) dh/dt = ?

b) dr/dt = ?

We know that

V = π*r²*h/3

and

tan ∅ = H/R = 2.5m / 1m = 2.5  ⇒ h/r = 2.5

⇒  h = (5/2)*r

⇒  r = (2/5)*h

If we apply

Q = dV/dt = -35 = d(π*r²*h/3)*dt

⇒  d(r²*h)/dt = 3*35/π = 105/π   ⇒   d(r²*h)/dt = -105/π

a) if   r = (2/5)*h

⇒  d(r²*h)/dt = d(((2/5)*h)²*h)/dt = (4/25)*d(h³)/dt = -105/π

⇒  (4/25)(3*h²)(dh/dt) = -105/π

⇒  dh/dt = -875/(4π*h²)

b) if  h = (5/2)*r

Q = dV/dt = -35 = d(π*r²*h/3)*dt

⇒  d(r²*h)/dt = d(r²*(5/2)*r)/dt = (5/2)*d(r³)/dt = -105/π

⇒  (5/2)*(3*r²)(dr/dt) = -105/π

⇒  dr/dt = -14/(π*r²)

Now, using h = 125 cm

dh/dt = -875/(4π*h²) = -875/(4π*(125)²)

⇒  dh/dt = -44.56*10⁻⁴ cm/s

then

h = 125 cm  ⇒  r = (2/5)*h = (2/5)*(125 cm)

⇒  r = 50 cm

⇒  dr/dt = -14/(π*r²) = - 14/(π*(50)²)

⇒  dr/dt = -17.82*10⁻⁴ cm/s

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