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Mariana [72]
3 years ago
5

A point charge Q moves on the x-axis in the positive direction with a speed of A point P is on the y-axis at The magnetic field

produced at the point P, as the charge moves through the origin, is equal to What is the charge Q?
Physics
1 answer:
oee [108]3 years ago
3 0

Answer: q = -52.5 μC

Explanation:

The complete question is given thus;

A point charge Q moves on the x-axis in the positive direction with a speed of 280 m/s. A point P is on the y-axis at y=+70mm. The magnetic field produced at the point P, as the charge moves through the origin, is equal to -0.30uTk. What is the charge Q? (uo=4pi x 10^-7 T m/A).

SOLVING:

from the given parameters we can solve this problem.

Given that the

Speed = 280 m/s

y = 70mm

B =  -30 * 10⁻⁶T

Using the equation for magnetic field we have;

Β = μqv*r / 4πr²

making q (charge) the subject of formula we have that;

q  = B * 4 *πr² / μqv*r

substituting the values gives us

q = (-0.3*10⁻⁶Tk * 4π * 0.07²) / (4π*10⁻⁷ * 280 ) = - [14.7 * 10⁻¹⁰k / 2.8 * 10⁻⁵ k ]

q = -52.5 μC

cheers i hope this helped !!!

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Answer:

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Explanation:

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7 0
2 years ago
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A 6.89-nC charge is located 1.76 m from a 4.10-nC point charge. (a) Find the magnitude of the electrostatic force that one charg
iogann1982 [59]

Answer: a) 8.2 * 10^-8 N or 82 nN and b) is repulsive

Explanation: To solve this problem we have to use the Coulomb force for two point charged, it is given by:

F=\frac{k*q1*q2}{d^{2}}

Replacing the dat we obtain F=82 nN.

The force is repulsive because the points charged have the same sign.

5 0
3 years ago
A car is traveling at a speed of 10m/s. A 0.5kg clump of mudis
CaHeK987 [17]

Answer:B

Explanation:

Given

speed of car v=10 m/s

mass of clump m=0.5 kg

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Since the tire is rotating about axle so a centripetal force is acting constantly on each particle towards the center of tire.

Centripetal force is given by

F_c=\frac{mv^2}{r}

where m=mass\ of\ element

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3 0
3 years ago
Question #4
IrinaVladis [17]
2) transverse



hope this helped:)
3 0
3 years ago
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What is the resistance of a 3.5 m copper wire (Rho= 1.7x10-8 Ohm·m) that 1 point
VikaD [51]

Answer:

(D)

Explanation:

Given :

l=3.5 m

A=5.26*10^{-6} m^{2}

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Resistance can be calculated as :

R=p\frac{l}{A} \\R=1.7*10^{-8} \frac{3.5}{5.26*10^{-6} }

R=\frac{5.95*10^{-2} }{5.26} \\R=1.13*10^{-2}

Resistance of the wire will be 1.1×10^{-2} ohms

Option D is correct

4 0
2 years ago
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