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Alona [7]
2 years ago
13

If the brakes are applied and the speed of the car is reduced to 12 m/s in 15 s , determine the constant deceleration of the car

.
Physics
1 answer:
zavuch27 [327]2 years ago
5 0

Given:

\triangle v = 12 m/s

Time = 15 s

To find:

Deceleration = ?

Formula used:

Deceleration is given by,

a = \frac{\triangle v}{t}

Solution:

Acceleration of the body is rate of increase of velocity. Deceleration of the body is negative acceleration i. e rate of decrease of velocity.

Thus, deceleration of the body is given by,

a = \frac{\triangle v}{t}

where a is the deceleration of the body

v is the velocity

\frac{\triangle v}{t} is rate of change of velocity

t is the time

a = \frac{12}{15}

a = 0.8 m/ s^{2}

Thus, deceleration is 0.8 m/ s^{2}.

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A motorboat accelerates uniformly from a velocity of 6.5m/s to the west to a velocity of 1.5m/s to the west. if its accelerate w
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7 0
3 years ago
In which of the following situations or places would you want to reduce the
sashaice [31]

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D

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<em>The correct answer would be in the axle of the wheels while you ride your bicycle.</em>

Options A, B, and C requires that the forces of friction is increased in order to have more control.

However, option D requires that there is a minimal frictional force in the axle of the wheels of a bicycle while riding so that a little effort would be required to keep the bicycle moving.

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4 0
3 years ago
What remains constant during the trajectory of an object
S_A_V [24]

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projectile

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3 0
3 years ago
Two 0.2304 cm x 0.2304 cm square aluminum electrodes, spaced 0.5974 mm apart are connected to a 61 V battery. What is the charge
Arisa [49]

Answer:

The charge on each plate is 0.0048 nC

Explanation:

for the distance between the plates d and given the area of plates, A, and ε = 8.85×10^-12 C^2/N.m^2, the capacitance of the plates is given by:

C = (A×ε)/d

   =[(0.2304×10^-2)(0.2304×10^-2)×(8.85×10^-12))/(0.5974×10^-3)

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then if the plates are connected to a battery of voltage V = 61 V, the charge on the plates is given by:

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Therefore, the charge on each plate is 0.0048 nC.

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2 years ago
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