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Alona [7]
3 years ago
13

If the brakes are applied and the speed of the car is reduced to 12 m/s in 15 s , determine the constant deceleration of the car

.
Physics
1 answer:
zavuch27 [327]3 years ago
5 0

Given:

\triangle v = 12 m/s

Time = 15 s

To find:

Deceleration = ?

Formula used:

Deceleration is given by,

a = \frac{\triangle v}{t}

Solution:

Acceleration of the body is rate of increase of velocity. Deceleration of the body is negative acceleration i. e rate of decrease of velocity.

Thus, deceleration of the body is given by,

a = \frac{\triangle v}{t}

where a is the deceleration of the body

v is the velocity

\frac{\triangle v}{t} is rate of change of velocity

t is the time

a = \frac{12}{15}

a = 0.8 m/ s^{2}

Thus, deceleration is 0.8 m/ s^{2}.

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Halley's comet orbits the sun roughly once every 76 years. It comes very close to the surface of the Sun on its closest approach
Licemer1 [7]

Answer:

r1 = 5*10^10 m , r2 = 6*10^12 m

v1 = 9*10^4 m/s

From conservation of energy

K1 +U1 = K2 +U2

0.5mv1^2 - GMm/r1 = 0.5mv2^2 - GMm/r2

0.5v1^2 - GM/r1 = 0.5v2^2 - GM/r2

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G = 6.67*10^-11 N.m^2/kg^2

0.5*(9*10^4)^2 - (6.67*10^-11*1.98*10^30/(5*10^10)) = 0.5v2^2 - (6.67*10^-11*1.98*10^30/(6*10^12))

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3 0
3 years ago
. Each valve A, B, and C, when open, releases water into a tank at its own constant rate. With all three valves open, the tank f
olasank [31]

Answer:

Time taken by A and B is 1.2 hr.

Explanation:

Given that

Time taken by tank when all(A+B+C) are open = 1 hr

Time taken by tank when A+C are open = 1.5 hr

Time taken by tank when B+C are open = 2 hr

If we treat as filling of tank is a work then

Work = time x rate

Lets take work is 1 unit

1 = 1(1/a+1/b+1/c)          ---------1

1 = 1.5(1/a+1/c)           ----------2

1 = 2(1/b+1/c)             --------3

From equation 1 and 3

1=1(1/a+1/2)

a=2

Form equation 2

1 = 1.5(1/2+1/c)

c=6

From equation 3

 1 = 2(1/b+1/6)  

b=3

So time taken by

A is alone to fill tank is 2 hr

B is alone to fill tank is 3 hr

C is alone to fill tank is 6 hr

So time\ taken\ by\ A\ and\ B =\dfrac{2\times 3}{2+3} hr

Time taken by A and B is 1.2 hr.

7 0
3 years ago
How far did an airplane go if it traveled at 700 mph for 3.5 hours?
Scrat [10]
2,450 miles. you have to do 700•3.5= 2,450
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Electron A falls from energy level X to energy level Y and releases blue light. Electron B falls from energy level Y to energy l
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