So, f[x] = 1/4x^2 - 1/2Ln(x)
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
Answer:
The graph g(x) is the graph f(x) vertically stretched by a factor of 7.
Step-by-step explanation:
Quadratic Equation: f(x) = a(bx - h)² + k
Since we are modifying the variable <em>a</em>, we are dealing with vertical stretch (a > 1) or vertical shrink (a < 1). Since a > 1 (7 > 1), we are dealing with a vertical stretch by a factor of 7.
Answer:
slope=.083
c=4
h=-0.333..
Step-by-step explanation:
Area of Big Rectangle Area of Small Rectangle
A = L x w A = L x w
= (25 + 2w)(10 + 2w) = 25 x 10
= 250 + 50w + 20w + 4w² = 250
Big - Small
74 = 250 + 70w + 4w² - 250
74 = 4w² + 70w
0 = 4w² + 70w - 74
= 2(2w² + 35w - 37)
= 2[2w² -2w | +37w - 37]
= 2[2w(w - 1) | +1(w - 1)]
= 2(2w + 1)(w - 1)
0 = 2 0 = 2w + 1 0 = w - 1
FALSE so disregard w = -1/2 w = 1
NEGATIVE so disregard
Answer: 1 meter
Answer:
x/3 ≤ 5
I'm not sure if this is what you were looking for. If not, please be more specific in your questions!
