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valentinak56 [21]
3 years ago
11

Bob has 6 more times than quarters. He has $1.65 in all. How many coins of each type does he have?

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
8 0

Answer:

3 quarters 9 dimes

Step-by-step explanation:

D=dimes

D-6=quarters

0.10 D + 0.25(D-6) = 1.65

0.10D + 0.25D - 1.5 = 1.65

0.35D = 3.15

Dibide both sides by 0.35

D =9

Q= D-6       Q = 9-6      Q=3

9*0.10 =90          3*0.25= 0.75

$0.75 + $0.90 =$ 1.65

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The first two terms of an arithmetic sequence are 7 and 4. Find the 7th term.
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EXPLANATION

If the first two terms of an arithmetic sequence are 7 and 4, then we know that an arithmetic sequence has a constant difference d and is defined by

a_n=a_1+(n+1)d

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