love Scenes That Went Too Far
I think it’s the number 3 I’m not sure I’m learning this stuff rn I’m getting the hang of it just it’s hard and not hard at the same time
Given:
8 tiles
radius from the center of the archway to the inner edge of the tile. 7 ft.
radius from the center of the archway to the outer edge of the tile. 8 ft = 7 ft + 1 ft.
Area of a semi circle = π r² / 2
A = (3.14 * (7ft)²) / 2 = (3.14 * 49ft²) / 2 = 153.86 ft² / 2 = 76.93 ft²
A = (3.14 * (8ft)²) / 2 = (3.14 * 64ft²) / 2 = 200.96 ft² / 2 = 100.48 ft²
100.48 ft² - 76.93 ft² = 23.55 ft²
23.55 ft² / 8 tiles = 2.94 ft² per tile.
Answer:
They lose about 2.79% in purchasing power.
Step-by-step explanation:
Whenever you're dealing with purchasing power and inflation, you need to carefully define what the reference is for any changes you might be talking about. Here, we take <em>purchasing power at the beginning of the year</em> as the reference. Since we don't know when the 6% year occurred relative to the year in which the saving balance was $200,000, we choose to deal primarily with percentages, rather than dollar amounts.
Each day, the account value is multiplied by (1 + 0.03/365), so at the end of the year the value is multiplied by about
... (1 +0.03/365)^365 ≈ 1.03045326
Something that had a cost of 1 at the beginning of the year will have a cost of 1.06 at the end of the year. A savings account value of 1 at the beginning of the year would purchase one whole item. At the end of the year, the value of the savings account will purchase ...
... 1.03045326 / 1.06 ≈ 0.9721 . . . items
That is, the loss of purchasing power is about ...
... 1 - 0.9721 = 2.79%
_____
If the account value is $200,000 at the beginning of the year in question, then the purchasing power <em>normalized to what it was at the beginning of the year</em> is now $194,425.14, about $5,574.85 less.
65.8 + 13.4 = 79 .2. So the answer is c
