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4 years ago

Need help with this problem! ASAP!

Mathematics

1 answer:

coldgirl [10]4 years ago

6 0

Answer: B .128 in^3

Step-by-step explanation:

The question is asking for the volume of the figure so multiply the length times the width times the height.

v= 8.2 * 4 * 3.9

v= 127.92 which rounds to 128.

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Please help.... simplify this expression

lana [24]

$\dfrac{\sqrt{-25}}{(5-2i)+(1-3i)}=\dfrac{5i}{6-5i}=\dfrac{5i(6+5i)}{36+25}=\dfrac{30i-25}{61}=\dfrac{-25+30i}{61}$

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3 years ago

How do i graph x+4y=8

Andrew [12]

Answer:

x = 8 y = 2

(8,2)

Step-by-step explanation:

You have to find the value of both x and y

x + 4y = 8

to find x you have to cancel out y so,

x + 4(0) = 8

x = 8

to find y you have to cancel out x

0 + 4y = 8

4y = 8

divide both sides by 4

y = 2

Hope this Helps!!!

6 0

3 years ago

A scale factor can never by greater than 1. True False

mr Goodwill [35]

True the scale factor can never ever be greater than 1.
Hope this helped <3

4 0

3 years ago

What is the multiplicative inverse of 6 1/8??

Semenov [28]

The multiplicative inverse of 6 1/8 (49/8) is

8/49

5 0

3 years ago

Read 2 more answers

In this 2x3 grid, each lattice point is one unit away from its nearest neighbors. A total of 14 isosceles triangles(but not righ

pickupchik [31]

The area of a shape is the amount of space it can occupy.

The number of isosceles triangle in the grid is: $\mathbf{\frac{2x^2}{u^2}}$

The dimension of the grid is given as:

$\mathbf{Dimension = x\ by\ x}$

Calculate the area

$\mathbf{A_1 = x\ \times \ x}$

$\mathbf{A_1 = x^2}$

The area of each isosceles triangle is given as:

$\mathbf{A_2 = \frac 12u^2}$

The number (n) of the triangle in an x-by-x grid is:

$\mathbf{n = A_1 \div A_2}$

So, we have:

$\mathbf{n = x^2 \div \frac 12u^2}$

Express as products

$\mathbf{n = x^2 \times \frac{2}{u^2}}$

$\mathbf{n = \frac{2x^2}{u^2}}$

Hence, the number of isosceles triangle in the grid is: $\mathbf{\frac{2x^2}{u^2}}$