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zheka24 [161]
2 years ago
8

Cameron invests $1000. He has a choice of two schemes:

Mathematics
1 answer:
Veronika [31]2 years ago
7 0

Answer: 2 year

Step-by-step explanation: After 3 years scheme B would be 80$ while Scheme A would be 75$

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Find each of the following for ​
KATRIN_1 [288]
<h2>Answer:</h2>

(a)

          f(x+ h)=8x+8h+3  

(b)

            f(x+ h)-f(x)=8h          

(c)

             \dfrac{f(x+ h)-f(x)}{h}=8

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as :

              f(x)=8x+3

(a)

           f(x+ h)

We will substitute (x+h) in place of x in the function f(x) as follows:

f(x+h)=8(x+h)+3\\\\i.e.\\\\f(x+h)=8x+8h+3

(b)

       f(x+ h)-f(x)              

Now on subtracting the f(x+h) obtained in part (a) with the function f(x) we have:

f(x+h)-f(x)=8x+8h+3-(8x+3)\\\\i.e.\\\\f(x+h)-f(x)=8x+8h+3-8x-3\\\\i.e.\\\\f(x+h)-f(x)=8h

(c)

           \dfrac{f(x+ h)-f(x)}{h}            

In this part we will divide the numerator expression which is obtained in part (b) by h to get:

           \dfrac{f(x+ h)-f(x)}{h}=\dfrac{8h}{h}\\\\i.e.\\\\\dfrac{f(x+h)-f(x)}{h}=8    

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If a product of three numbers is 3150, two of the numbers are 14,15. Find the third number
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Answer:

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proof on pic......................

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