The time it takes the Polonium-194 to decay to 1/16 of its original amount is 2.8 seconds.
<h3>What is half-life?</h3>
half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay
To calculate the time it takes the sample of Polonium-196 to decay to 1/16 of its original amount, we use the formula below
Formula:
- = R/R'......... Equation 1
Where:
- n = Total number of time it takes Polonium-194 to decay to 1/16 of its original amount
- t = Half-life of Polonium-194
- R = Original amount of Polonium-194
- R' = Amount of Polonium-194 after decay
From the question,
Given:
Substitute these values into equation 1 and solve for n
Equating the base,
- n/0.7 = 4
- n = 0.7×4
- n = 2.8 seconds.
Hence, the time it takes the Polonium-194 to decay is 2.8 seconds.
Learn more about half-life here: brainly.com/question/25750315
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Boiling water has a lot more heat than the oven's air (even though the air has a higher temperature). ... A match has a greater temperature than the iceberg because the average molecule in the match is moving faster than the average molecule in the iceberg
Answer:
f = - 20 cm
Explanation:
This exercise asks us for the focal length, which for a lens in air is
1 / f = (n₂-n₁) (1 / R₁ - 1 / R₂)
where n₂ is the refractive index of the material, n₁ is the refractive index of the medium surrounding the lens, R₁ and R₂ are the radii of the two surfaces.
In this exercise the medium that surrounds the lens is air n₁ = 1 and the lens material has an index of refraction n₂ = n = 1.50, let's substitute in the expression
- 1/40 = (n-1) (1 / R₁ -1 / R₂)
(1 / R₁ - 1 / R₂) = - 1/40 (n-1)
let's calculate
(1 / R₁ -1 / R₂) = - 1/40 (1.50 -1)
(1 / R₁ -1 / R₂) = -1/20
Now we change the construction material for one with refractive index
n = 2, keeping the radii,
1 / f = (n-1) (1 / R₁-1 / R₂)
1 / f = (n-1) (-1/20)
let's calculate
1 / f = (2.00-1) (-1/20)
1 / f = -1/20
f = - 20 cm