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3 years ago

A 800 kg car is traveling a 4.5 m/s. What is the momentum of the truck?

Physics

1 answer:

ad-work [718]3 years ago

4 0

Answer:

3600 kg m/s

Explanation:

Momentum can be calculate using the following formula:

p=m*v

where p is the momentum in kg m/s, m is the mass in kilograms, and v is the velocity in m/s.

We know the mass of the car is 800 kilograms and the car is traveling at 4.5 m/s. So, m=800 and v=4.5 Therefore, we can substitute 800 for m and 4.5 for v.

p=m*v

p=800*4.5

Multiply

p=3600

The momentum is 3600 kg m/s

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A thin block of soft wood with a mass of 0.072 kg rests on a horizontal frictionless surface. A bullet with a mass of 4.67 g is

Olegator [25]

Answer:

366.90149 m/s

923.821735 J

324.734 J

Initial Kinetic energy > Final kinetic energy

Explanation:

$m_1$ = Mass of block = 0.072 kg

$m_2$ = Mass of bullet = 4.67 g

$u_1$ = Initial Velocity of block = 0

$u_2$ = Initial Velocity of bullet = 629 m/s

$v_1$ = Final Velocity of block = 17 m/s

$v_2$ = Final Velocity of bullet

In this system the linear momentum is conserved

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}\\\Rightarrow v_2=\frac{m_{1}u_{1}+m_{2}u_{2}-m_1v_1}{m_2}\\\Rightarrow v_2=\frac{0.072\times 0+4.67\times 10^{-3}\times 629-0.072\times 17}{4.67\times 10^{-3}}\\\Rightarrow v_2=366.90149\ m/s$

Final Velocity of bullet is 366.90149 m/s

The initial kinetic energy

$K_i=\frac{1}{2}m_2u_2^2\\\Rightarrow K_i=\frac{1}{2}4.67\times 10^{-3}\times 629^2\\\Rightarrow K_i=923.821735\ J$

The final kinetic energy

$K_f=\frac{1}{2}m_2v_2^2+\frac{1}{2}m_1v_1^2\\\Rightarrow K_f=\frac{1}{2}4.67\times 10^{-3}\times 366.90149^2+\frac{1}{2}0.072\times 17^2\\\Rightarrow K_f=324.734\ J$

Initial Kinetic energy > Final kinetic energy

3 0

3 years ago

A resistor with r = 340 ω and an inductor are connected in series across an ac source that has voltage amplitude 490 v. The rate

Arada [10]

The value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.

<h3>What is impedance Z of the circuit?</h3>

The impedance Z of the circuit is the ratio of voltage amplitude to the maximum current.

$Z=\dfrac{V}{I}$

Here, <em>V </em>is voltage amplitude and<em> I</em> maximum current.

A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 490V. The rate at which electrical energy is dissipated in the resistor is 316 W.

The rate at which electrical energy is dissipated in the resistor is the product of the resistance and the square of current. Thus,

$316=340\times I^2\\I=\sqrt{\dfrac{316}{340}}\\I=0.964\rm\; A$

The impedance Z of the circuit is,

$Z=\dfrac{V}{I}\\Z=\dfrac{490}{0.964}\\Z=508\rm\; ohm$

Thus, the value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.

Learn more about the impedance Z of the circuit here:

brainly.com/question/24225360

#SPJ4

5 0

2 years ago

Shelby travels 6 meters East, 2 meters North, 3 meters West, and then 2 meters South. What is their displacement?

yaroslaw [1]

Answer:

3 m

Explanation:

At last, Same line; so, 6-3 = 3

7 0

3 years ago

Balancing equations<br>

kolbaska11 [484]

Answer:

Tips for Balancing Chemistry Equations You may only put numbers in front of the molecules. You can never alter the subscript, as it would alter the formula. ... Begin by counting and making note of the elements present on each side of the equation. Count the number of molecules of each element on both sides of the equation. More items...

Explanation:

I dont know what the question is

3 0

3 years ago

All household circuits are wired in parallel. A 1140-W toaster, a 270-W blender, and a 80-W lamp are plugged into the same outle

VARVARA [1.3K]

Answer:

total current = 12.417 A

so it will not fuse as current is less than 15 A

Explanation:

given data

toaster = 1140-W

blender = 270-W

lamp = 80-W

voltage = 120 V

solution

we know that current is express as

current = power ÷ voltage ......................1

here voltage is same in all three device

current by toaster is

I = $\frac{1140}{120}$

I = 9.5 A

and

current by blender

I = $\frac{270}{120}$

I = 2.25 A

and

current by lamp is

I = $\frac{80}{120}$

I = 0.667 A

so here device in parallel so

total current is = 9.5 A + 2.25 A + 0.667 A

total current = 12.417 A

so it will not fuse as current is less than 15 A

8 0

3 years ago