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3 years ago

8

Graph the function f(x)=3/2x−4. Use the line tool and select two points to graph.

2 answers:

luda_lava [24]3 years ago

7 0

The answer will be 0-4

Anton [14]3 years ago

3 0

Anwser: would be (2,-4) hope this helps if not im sorry

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Factor the expression completely over the complex numbers. y^4+14y^2+49 <br> PLZ HELP ASAP

Gre4nikov [31]

there is the explenation

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3 years ago

If 2x + 8 = 16, what is the vaule of x + 4?

Ghella [55]

Answer:

your answer

Step-by-step explanation:

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3 years ago

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Which of the following statements are true of the hypotenuse of a right triangle?

OLEGan [10]

The hypotenuse is always the longest side, and it is always opposite the right angle.
"Leg" is not a mathematical term. If it is being used to refer to one of the sides forming a right angle, the hypotenuse is not a "leg".

8 0

3 years ago

Can someone help me with this problem asap

xenn [34]

Answer:

f(x) = $x^4 - 2x^3 + 49x^2 - 18x + 360$ is the required polynomial.

Step-by-step explanation:

Given the zeroes (roots) of the polynomial are $-3i$ and $2 + 6i$ .

We know that complex roots occur in conjugate pairs.

So, this means that $+3i$ and $2 - 6i$ would also be the roots of the polynomial.

If $\pm 3i$ are to be the roots of the polynomial then the polynomial should have been: $x^2 + 9 = 0$ .

Now, to determine the polynomial for which $2 \pm 6i$ would be the roots.

Roots of the polynomial are nothing but the values of x (any variable) that would make the polynomial zero.

⇒ $x = 2 + 6i \hspace{35mm} x = 2 - 6i$

⇒ $x - 2 - 6i = 0 \hspace{25mm} x - 2 + 6i = 0$

The required polynomial would be the product of all the above polynomials.

$i.e., (x^2 + 9)(x - 2 + 6i)(x - 2 - 6i) = 0$

Multiply this to get the required equation.

⇒ $(x^2 + 9)(x^2 - 2x + 40)$

$\implies x^4 - 2x^3 + 40x^2 + 9x^2 - 18x + 360 = 0$

∴ The required polynomial is x⁴ - 2x³ + 49x² - 18x + 360 = 0.

3 0

3 years ago

Find all the square roots of x^2 ≡ 53 (mod 77) by hand. This is my second post. Please explain all the steps how you did this?

sasho [114]

Answer:

Step-by-step explanation:

Given that

$x^2 ≡ 53 (mod 77)$

Right side has values as

53, 53+77, 53+2(77),+....

We have to find one which is a perfect square.

We have from this series 361 is 19 square

Thus $x =19.$

Next is $x^2=900\\x=30$

$x^2=2209\\x=47$ and so on.

3 0

3 years ago