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lana66690 [7]
3 years ago
5

Calculate the pressure exerted on the heel of a boy’s foot if the boy weighs 80 N and he lands on one heel,which has an area of

16 cm2.
Physics
1 answer:
cricket20 [7]3 years ago
3 0

Pressure at a given surface is given as ratio of normal force and area

so here force due to heel of the shoes is given as 80 N

and the area of the heel is given as 16 cm^2

so we can say

P = \frac{F}{A}

here we have

F = 80 N

A = 16 cm^2 = 16 * 10^{-4} m^2

P = \frac{80}{16 * 10^{-4}}

P = 5 * 10^4 N/m^2

so pressure at the surface due to its heel will be 5 * 10^4 N/m^2

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Answer:

the period of the 16 m pendulum is twice the period of the 4 m pendulum

Explanation:

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SInce both pendulums are at the same place, "g" is the same for both, and when we compare the two periods, we get:

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Explanation:

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m=\dfrac{-(-37.5)}{(-21.09)}

m = -1.77

So, the magnification produced by the mirror is (-1.77). Hence, this is the required solution.

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