Answer:
I will answer this in English, we can translate it to:
Why if you charge a mate by an amount of time you are not doing work?
This happens because work is defined as the displacement done by a force:
W = d*F
where W is work, d is the distance, and F is the force.
This means that the amount of time that you are charging your mate does not affect the mechanical work, the only time that you are doing work is when you are lifting him.
The difference in the mass of carbon dioxide in 500 kg of air in 2013 compared to 1800 is 0.06 Kg
<h3>Data obtained from the question</h3>
- Year 1800 percent = 0.028%
- Year 2013 percent = 0.040%
- Mass of air = 500 Kg
- Difference =?
<h3>How to determine the mass of CO₂ in 500 Kg in year 1800</h3>
- Year 1800 percent = 0.028%
- Mass of air = 500 Kg
- Mass of CO₂ =?
Mass = percent × mass of air
Mass of CO₂ = 0.028% × 500
Mass of CO₂ = 0.14 Kg
<h3>How to determine the mass of CO₂ in 500 Kg in year 2013</h3>
- Year 1800 percent = 0.040%
- Mass of air = 500 Kg
- Mass of CO₂ =?
Mass = percent × mass of air
Mass of CO₂ = 0.040% × 500
Mass of CO₂ = 0.2 Kg
<h3>How to determine the difference</h3>
- Mass of CO₂ in year 1800 = 0.14 Kg
- Mass of CO₂ in year 2013 = 0.2 Kg
- Difference =?
Difference = mass in 2013 - mass in 1800
Difference = 0.2 - 0.14
Difference = 0.06 Kg
Learn more about composition:
brainly.com/question/11617445
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If you mean pattern designs it’s rocky bumpy and you can see the circle patterns
If you mean phases the here’s a picture
