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2 years ago

15

What is the LCD of

}" align="absmiddle" class="latex-formula"> and $\frac{7}{10}$

1 answer:

dezoksy [38]2 years ago

4 0

LCD of denominators.

Multiples of 5: 0, 5, 10, 15, 20, 25, ...

Multiples of 10: 0, 10, 20, 30, 40, ...

LCD(5, 10) = 10

$\dfrac{2}{5}=\dfrac{2\cdot2}{5\cdot2}=\dfrac{4}{10}$

$\dfrac{7}{10}=\dfrac{7}{10}$

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OK here's the deal, I need to graph F(x)=x^2 and F(x)=2^x as functions. I've run completely out of options, I've graphed them as

butalik [34]

Answer:

see attached graph

Step-by-step explanation:

You graphs look fine. The only thing I can think of without seeing the question itself, its that perhaps the teacher wants them on the same graph?

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2 years ago

CAN SOMEONE PLEASE HELP ME???

d1i1m1o1n [39]

Answer:

Option D, x = 4

Step-by-step explanation:

Option A: y = 4 doesn't work because that line would be horizontal

Option B: y = 4x doesn't work because that would be diagnol

Option C: x = -4 doesn't work because that would a vertical line at -4

<em>Option D: x = 4 works because that would a vertical line at 4</em>

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Answer: Option D, x = 4

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3 years ago

The cruise boat can carry up to 45 passengers. The company wants to know the minimum number of passengers needed per cruise to c

denpristay [2]

Fixed price costs
Crew salaries 350
fuel 120
overheads 170
Total fixed cost: 640

Variable costs per passenger
refreshments   $ 6.50
refund   $ 3.64
total variable cost: 10.14

Sales income
<span>Average ticket $ 36 .40

</span><span>Break-even point = <u> (fixed costs)   </u>
(income per passenger – costs per passenger) </span><span>

</span>
Break even = 640 / (36.40-10.14) = 640 / 26.26 = 24.37

3 0

2 years ago

What is the value of k in the equation k/3 - 5 = 34?<br> 11 1/3<br> 13<br> 102<br> 117

mestny [16]

1. Add 5 to both sides

k/3 = 34 + 5

2. Simplify 34 + 5 to 39

k/3 = 39

3. Multiply both side by 3

k = 39 * 3

4. Simplify 39 * 3 to 117

k = 117

6 0

2 years ago

Read 2 more answers

The number of people arriving for treatment at an emergency room can be modeled by aPoisson process with a rate parameter of 5/h

saveliy_v [14]

Answer:

(a) The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is 3.75 arrivals.

Step-by-step explanation:

(a) If the arrivals can be modeled by a Poisson process, with λ = 5/hr, the probability of having exactly four arrivals during a particular hour is:

$P(X=4)=\frac{\lambda^{X}*e^{-\lambda} }{X!} =\frac{5^{4}*e^{-5} }{4!}=\frac{625*0.006737947}{24} =\frac{4.211}{24}=0.1754$

The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour can be written as

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))$

Using

$P(X)=\frac{\lambda^{X}*e^{-\lambda} }{X!}$

We get

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))\\P(X>3)=1-(0.0067+ 0.0337+ 0.0842 + 0.1404 )\\P(X>3)=1-0.2650=0.7350\\$

The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is

$EV=\lambda*t=5*0.75=3.75$

8 0

2 years ago