The following are the answers to
the questions presented:
Part 1:
Vertex: <span>(<span><span>−3</span>/ 2</span>,<span> 11/2</span>)</span>
Axis of
symmetry = x = -3/2
Domain = all
real numbers
Range = <span>y </span><span>≤ </span>11/2
Part 2:
A quadratic equation is symmetrical around its vertex. The
equation for the axis of symmetry is x = -3/2 since the equation is in terms of
x. Since no value of x is undefined, then the domain of the equation is clearly
all real numbers. Since the value of “a” is negative, then that means the y
coordinate of the vertex is the maximum value so the range will never get above
11/2. I am hoping that these answers have satisfied your queries and it
will be able to help you in your endeavors, and if you would like, feel free to
ask another question.
Answer: B
Step-by-step explanation:
(opp/hyp)=sin60
opp=2sqr(3)x(sqr(3)/2)
opp=3
1,300 because 8 is over 5 and it rounds the 100th place ,(which is 2), to become a 3 which makes the answer 1,300.
Answer:
A
Step-by-step explanation:
The formula is y-b=m(x-a)
m is the slope
a is the x term
b is the y term
y-6=3(x-5)
Answer:
9 hours
Step-by-step explanation:
12x+32=140
so
140-32=108
108/12= 9
x=9
