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3 years ago

At the market, 8 batteries cost \$10dollar sign, 10. How much do 6 batteries cost? \$

Mathematics

2 answers:

Len [333]3 years ago

8 0

Answer:

7.5

Step-by-step explanation:

o-na [289]3 years ago

5 0

8 batteries = $10

6 batteries = x

x = cost of 6 batters in dollars

Step: cross multiply

8x = 10*6

x = 60/8

x = 7.5

6 batteries cost $7.5

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After my salary was increased by $16\%,$ it was $\$52{,}200$. What was my salary before the increase?

boyakko [2]

The salary before the increase was $48000.

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3 years ago

Fiind the value of x between 0 and 360 <br>for question 5sin 2x=7cos2x

Degger [83]

Answer:

x=pi*n/2+1/2arctan(7/5)

Step-by-step explanation:

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3 years ago

Write the percent as a fraction or mixed number in simplest form.<br><br> 0.8%

Oxana [17]

Answer:

4/5

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3 years ago

Read 2 more answers

2x^2+9x+6=0 quadtratic equation

Studentka2010 [4]

Hello from MrBillDoesMath!

Answer:

x = ( -9 + sqrt(33) ) /4

and

x = ( -9 - sqrt(33) ) /4

Discussion:

Using the quadratic formula with a = 2, b = 9 and c = 6 gives

x = ( -b +\- sqrt(b^2-4ac) )/2a

x = ( -9 +\- sqrt(9^2 - 4*2*6)) / (2*2) =>

x = ( -9 +\- sqrt (81- 48)) / 4 =>

x = ( -9 +\- sqrt(33) ) /4

Thank you,

MrB

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3 years ago

A study by Allstate Insurance Co. finds that 82% of teenagers have used cell phones while driving (the Wall Street Journal, May

Strike441 [17]

The probability that the sample proportion is within ± 0.02 of the population proportion is 0.3328

<h3>How to determine the probability?</h3>

The given parameters are:

Sample size, n = 100
Population proportion, p = 82%

Start by calculating the mean:

$\mu = np$

$\mu = 100 * 82\%$

$\mu = 82$

Calculate the standard deviation:

$\sigma = \sqrt{\mu(1 - p)$

$\sigma = \sqrt{82 * (1 - 82\%)$

$\sigma = 3.84$

Within ± 0.02 of the population proportion are:

$x_{min} = 82 * (1 - 0.02) = 80.38$

$x_{max} = 82 * (1 + 0.02) = 83.64$

Calculate the z-scores at these points using:

$z = \frac{x - \mu}{\sigma}$

So, we have:

$z_1 = \frac{80.36 - 82}{3.84} = -0.43$

$z_2 = \frac{83.64 - 82}{3.84} = 0.43$

The probability is then represented as:

P(x ± 0.02) = P(-0.43 < z < 0.43)

Using the z table of probabilities, we have:

P(x ± 0.02) = 0.3328

Hence, the probability that the sample proportion is within ± 0.02 of the population proportion is 0.3328