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masya89 [10]
2 years ago
10

Can someone help me with this question

Mathematics
1 answer:
gavmur [86]2 years ago
3 0

Answer:

w = 2.6

x = 26.2^\circ

Step-by-step explanation:

Solving for w:

Look at the right triangle on the left side. It has a 32-deg angle, a hypotenuse of length 5, and a leg of length w. For the 32-deg angle, w is the opposite leg. We have an opposite leg and a hypotenuse, so we use the sine.

\sin A = \dfrac{opp}{hyp}

\sin 32^\circ = \dfrac{w}{5}

w = 5 \sin 32^\circ

w = 2.6495

w = 2.6

Solving for x:

Now look at the right triangle on the right side. There is an acute angle measuring x, an opposite leg measuring 2.6495 (from the solution above), and a hypotenuse measuring 6. We use the sine again.

\sin A = \dfrac{opp}{hyp}

\sin x = \dfrac{w}{6}

\sin x = \dfrac{2.6495}{6}

\sin x = 0.441599

Since we know what the sine of angle x is equal to, and we want to know the measure of angle x, we use the inverse sine function, also called the arcsine.

x = \sin^{-1} 0.441599

x = 26.2^\circ

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the area of the triangle below is 1/4 square meters. what is the length of the base. express your answer in simplest form
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Answer:

4/5

Step-by-step explanation:

<u>Given</u>,

Area of the triangle = 1/4 square meters

From the diagram,

Height = 2/5 m

<u>To find</u> : Length of the base

<u>Formula</u> : -

A = bh/2

Here,

A denotes Area

b denotes Base

h denotes Height

A = 1/4

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Cross multiply,

A * 2 = bh

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2 * (1/4) = b * (2/5)

(1 * 2)/4 = (b * 2)/5

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Cross multiply,

1 * 5 = 2 * 2b

5 = 4b

b = 4/5 meters

Hence,

The length of the base is 4/5 meters.

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