Question

Jude says that the volume of a square pyramid with base edges of 12 in and a height of 10 in is equal to the volume of a cylinder with a radius of 6.77 in and a height of 10 in. Jude rounded his answers to the nearest whole numbers. Examine Jude's calculations. Is he correct?
Volume of Square Pyramid Volume of Cylinder
V = one third B(h) V = one thirdπr2h
V = one third(144)(10) V = one thirdπ(6.772)(10)
V = one third(1440) one thirdπ(45.8329)(10)
V = 480 in3 V = one thirdπ(458.329)
V ≈ 480 in3

Yes, his calculations are correct and the volumes for figures are equal.
No, he made a mistake in solving for the volume of the cylinder.
Yes, but he made a mistake in solving for the volume of the square pyramid.
No, he made a mistake in solving for the volume of both figures.

Answer 1

Answer:

No, not correct

Step-by-step explanation:

Square pyramid volume:  (1/3) (base area)(height).  In this case,

V = (1/3)*(12 in)^2*(10 in) = 480 in^3 = 480 in^3

Cylinder volume:  (base area)*(height).  In this case,

V = (3.14)*(6.77 in)^2*(10 in) = 452.12 in^3.

No, Jude is not correct; the 480 in^3 volume of the square pyramid is not the same as the 452.12 in^3 volume of the cylinder.

Answer 2

Answer:

Choice #2 (B) - No, he made a mistake in solving for the volume of the cylinder.

Step-by-step explanation:

If your on Question 10 of 06.01 MC, that should be your answer.