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Harlamova29_29 [7]

2 years ago

7

Wade has a test score of 77%on his first test and 65% on his second test what must be the third test score to have an average of

80%

2 answers:

Alisiya [41]2 years ago

8 0

Answer:

98

Step-by-step explanation:

(77 + 65 + x) / 3 = 80

142 + x = 240

x = 98

Rudiy272 years ago

6 0

the last score has to be 98% for the average to be 80%

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What is the speed that a car reaches in m/s, if it travels 956km in 56sec?Help me!! MRU (Uniform Rectilinear Movement)

In-s [12.5K]

Answer:

17.07m/s

Step-by-step explanation:

v=d/t

d=956km

t=56sec

v=956/56

v=17.07m/s

8 0

2 years ago

Colin invests £2350 into a savings account. The bank gives 4.2% compound

marin [14]

Answer:

Answer:

£3692

Step-by-step explanation:

A = p(1 + r/n)^nt

Where,

A = future value

P = principal = £2350

r = interest rate = 4.2% = 0.042

n = number of periods = 1(annual)

t = time = 4 years

A = p(1 + r/n)^nt

= 2350(1 + 0.042/1)^1*4

= 2350(1 + 0.042)^4

= 2350(1.042)^4

= 2350(1.5789)

= 2770.42

A = £2770.42

Total years = 10

Remaining years = 10 – 4

= 6 years

Remaining 6 years

P = £2770.42

r = 4.9% = 0.049

n = 1

t = 6

A = p(1 + r/n)^nt

= 2770.42(1 + 0.049/1)^1*6

= 2770.42(1 + 0.049)^6

= 2770.42(1.049)^6

= 2770.42(1.3325)

= 3691.59

A = £3691.59

Approximately £3692

Thank you!

5 0

2 years ago

55% as a fraction in simplest form.

nirvana33 [79]

Answer: 11/20
55/100 simplified is 11/20

3 0

2 years ago

The volume of a cone of radius r and height h is given by V=πr²h³. If the radius and the height both increase at a constant rate

Aloiza [94]

Answer:

The volume of cone is increasing at a rate 1808.64 cubic cm per second.

Step-by-step explanation:

We are given the following in the question:

$\dfrac{dr}{dt} = 12\text{ cm per sec}\\\\\dfrac{dh}{dt} = 12\text{ cm per sec}$

Volume of cone =

$V = \dfrac{1}{3}\pi r^2 h$

where r is the radius and h is the height of the cone.

Instant height = 9 cm

Instant radius = 6 cm

Rate of change of volume =

$\dfrac{dV}{dt} = \dfrac{d}{dt}(\dfrac{1}{3}\pi r^2 h)\\\\\dfrac{dV}{dt} = \dfrac{\pi}{3}(2r\dfrac{dr}{dt}h + r^2\dfrac{dh}{dt})$

Putting values, we get,

$\dfrac{dV}{dt} = \dfrac{\pi}{3}(2(6)(12)(9) + (6)^2(12))\\\\\dfrac{dV}{dt} =1808.64\text{ cubic cm per second}$

Thus, the volume of cone is increasing at a rate 1808.64 cubic cm per second.

5 0

2 years ago

Given: <br><br>EM, EQ-secants<br><br>Prove: MP·EW=WQ·EP

Dennis_Churaev [7]

Answer:

Step-by-step explanation:

A secant is a straight line from a point outside a given circle that passes through two points on its circumference.

From the given diagram, EM and EQ are secants.

Thus,

<PEW ≅ <WEP (common angles)

<EMP ≅ <EQW (secant-chord theorem)

<WMP ≅ <PQM (inscribed angles of arc WP)

Therefore,

$\frac{EW}{WM}$ = $\frac{EP}{PQ}$ (corresponding sides of a triangle)

This implies that,

EW*PQ = EP*WM

Therefore,

MP*EW = WQ*EP (properties of a similar triangle)

7 0

2 years ago