Answer:
La aceleración necesaria para detener el avión es - 10.42 m/s².
Explanation:
Un movimiento uniformemente acelerado (M.U.A) es aquél cuya aceleración es constante y la velocidad de un objeto cambia a medida que el movimiento evoluciona.
Siendo la aceleración "a" el cambio de velocidad al tiempo transcurrido en un punto A a B, la velocidad inicial la velocidad que tiene un cuerpo al iniciar su movimiento en un período de tiempo y la velocidad final la velocidad que tiene un cuerpo al finalizar su movimiento en un período de tiempo, entonces en M.U.A se cumple:
Vf² - Vo² = 2*a*d
donde:
- Vf: Velocidad final
- Vo: Velocidad inicial
- a: Aceleración
- d: Distancia recorrida
En este caso:
- Vf: 0 m/s, porque el avión se detiene
- Vo: 50 m/s
- a: ?
- d: 120 m
Reemplazando:
(0 m/s)² - (50 m/s)² = 2*a*120 m
Resolviendo:
a= - 10.42 m/s²
<u><em>La aceleración necesaria para detener el avión es - 10.42 m/s².</em></u>
The wavelength of the infrared radiation is λ = 
×
m.
<h3>What is infrared radiation?</h3>
An infrared telescope is tuned to detect infrared radiation with a frequency of 9.45 THz.
We know that,
1 THz = 10¹² Hz
So,
f = 9.45 × 10¹² Hz
We need to find the wavelength of the infrared radiation.
λ=c/f
λ = 3×
/9.45×
λ = 3.174 × m
The term "infrared radiation" (IR) refers to a part of the electromagnetic radiation spectrum with wavelengths between about 700 nanometers (nm) and one millimeter (mm). Longer than visible light waves but shorter than radio waves are infrared waves.
Electromagnetic radiation with wavelengths longer than those of visible light is known as infrared, also known as infrared light. Since it is undetectable to the human eye, The typical range of wavelengths considered to be infrared (IR) is from about 1 millimeter to the nominal red edge of the visible spectrum, or about 700 nanometers.
To learn more about infrared radiation from the given link:
brainly.com/question/13163856
#SPJ4
Answer:
Data:-m=0.88kg ,g=9.8m/sec² ,P.E=96J ,h=?
Explanation:
solution ,P.E=mgh here we have to find h so h=P.E/mg ,h=96/0.88×9.8 ,h=96/8.624=11.131m and if you want to verify so just put the value of h in same formula, likewise :-P.E=mgh ,P.E=0.88×9.8×11.131=96J so we got the same value of P.E as it is given the question (verified).
Answer:
Maximum height reached by the ball is 32 meters.
Explanation:
It is given that,
If a baseball is project upwards from the ground level with an initial velocity of 32 feet per second, then it's height is a function of time. The equation is given as :
...........(1)
t is the time taken
s is the height attained as a function of time.
Maximum height achieved can be calculated as :
-16 t + 32 = 0
t = 2 seconds
Put the value of t in equation (1) as :
s = 32 meters
So, the maximum height reached by the ball is 32 meters. Hence, this is the required solution.
