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kow [346]
3 years ago
13

What can you say about the nd behavior of the function f(x)=-4

tle="x^{6}" alt="x^{6}" align="absmiddle" class="latex-formula">+x^{2}-52
Mathematics
1 answer:
kvasek [131]3 years ago
6 0

Answer: right side = as x → ∞, y → -∞  & left side = as x → -∞, y → -∞

<u>Step-by-step explanation:</u>

To find end behavior, we need to evaluate 2 things: Sign of the leading coefficient and Degree of the function.

Sign: Determines the end behavior of the right side.

  • Positive: right side goes to positive infinity
  • Negative: right side goes to negative infinity

Degree: Determines the end behavior of the left side

  • Odd: left side is opposite of right side
  • Even: left side is same as right side

f(x) = -4x⁶ + x² - 52

1. Sign is negative so right side goes to negative infinity (as x → ∞, y → -∞)

2. Degree is even so left side is the same as right side so it also goes to negative infinity (as x → -∞, y → -∞)

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F(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-%5Csqrt%7Bx%5E2%2B2x-15%7D" id="TexFormula1" title="\sqrt{x+7} -\
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Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

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find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

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)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

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