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Ainat [17]
3 years ago
12

Find an equation of the line. Write the equation using function notation. Through (3, -3); perpendicular to 5y= x-10

Mathematics
1 answer:
svet-max [94.6K]3 years ago
3 0

\bf 5y=x-10\implies y=\cfrac{x-10}{5}\implies \stackrel{slope}{y=\stackrel{\downarrow }{\cfrac{1}{5}}x-2} \\\\\\ \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{1}{5}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{5}{1}}\qquad \stackrel{negative~reciprocal}{-\cfrac{5}{1}\implies -5}}


so we're really looking for the equation of a line whose slope is -5 and runs through 3, -3.


\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{-3})~\hspace{10em} slope = m\implies -5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-3)=-5(x-3) \\\\\\ y+3=-5x+15\implies \stackrel{y}{f(x)}=-5x+12

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Step-by-step explanation:

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Answer:

The proportional table in the attached figure

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line <u><em>and the line passes through the origin</em></u>

<em>Verify each table</em>

Find the value of the constant of proportionality k for each ordered pair of a table.

k=\frac{y}{x}

If all the values of k are the same, then the table represent a proportional relationship between x and y

Table 1

For x=1, y=2 ----> k=\frac{2}{1}=2

For x=2, y=4 ----> k=\frac{4}{2}=2

For x=3, y=8 ----> k=\frac{8}{3}=2.7

The values of k are not equal

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This table not represent a proportional relationship between x and y

Table 2

For x=0, y=4

The line not passes through the origin

so

This table not represent a proportional relationship between x and y

Table 3

For x=0, y=0 ----> is OK the line passes though the origin

For x=1, y=1 ----> k=\frac{1}{1}=1

For x=2, y=4 ----> k=\frac{4}{2}=2

The values of k are not equal

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This table not represent a proportional relationship between x and y

Table 4

For x=1, y=4 ----> k=\frac{4}{1}=4

For x=2, y=8 ----> k=\frac{8}{2}=4

For x=3, y=12 ----> k=\frac{12}{3}=4

The values of k are the same

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This table represent a proportional relationship between x and y

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Finish by substituting both variables to solve for \angle ABC:

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