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katrin2010 [14]
4 years ago
9

Determine whether 4 is a solution of the equation 9x+7=40. Is 4 a​ solution?

Mathematics
2 answers:
Allisa [31]4 years ago
5 0

Plug in 4 for x

9(4) + 7 = 40

36 + 7 = 40

43 ≠ 40

No, 4 is not a solution

hope this helps

notka56 [123]4 years ago
4 0

Question:

Determine whether 4 is a solution of the equation 9x+7=40.

Is 4 a​ solution?

Solution:

9(4) + 7 = 40

= 36 + 7

= 43

Final Answer:

4 is not a solution

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Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.
WINSTONCH [101]

Answer:

a) y(t) = y_{0}e^{4t} + 2. It does not have a steady state

b) y(t) = y_{0}e^{-4t} + 2. It has a steady state.

Step-by-step explanation:

a) y' -4y = -8

The first step is finding y_{n}(t). So:

y' - 4y = 0

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

r - 4 = 0

r = 4

So:

y_{n}(t) = y_{0}e^{4t}

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

y_{p}(t) = C

So

(y_{p})' -4(y_{p}) = -8

(C)' - 4C = -8

C is a constant, so (C)' = 0.

-4C = -8

4C = 8

C = 2

The solution in the form is

y(t) = y_{n}(t) + y_{p}(t)

y(t) = y_{0}e^{4t} + 2

b) y' +4y = 8

The first step is finding y_{n}(t). So:

y' + 4y = 0

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

r + 4 =

r = -4

So:

y_{n}(t) = y_{0}e^{-4t}

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

y_{p}(t) = C

So

(y_{p})' +4(y_{p}) = 8

(C)' + 4C = 8

C is a constant, so (C)' = 0.

4C = 8

C = 2

The solution in the form is

y(t) = y_{n}(t) + y_{p}(t)

y(t) = y_{0}e^{-4t} + 2

6 0
3 years ago
Determine a polynomial that represents the area of the parallelogram.<br> A=
sp2606 [1]

Answer:

4b² - 16

Step-by-step explanation:

The formula to find the area of a parallelogram equals bh, where b = base and h - height. We're given the base as 2b + 4 and the height as 2b - 4.

  • (2b+4)*(2b-4)=(2b+4)(2b-4)
  • (2b+4)(2b-4)=(2b)(2b)+(2b)(-4)+(4)(2b)+(4)(-4)
  • 4b^2-8b+8b-16
  • 4b^2-16

Therefore, the answer is 4b² - 16.

6 0
2 years ago
Simplify.<br><br> 5x+3(x+2)+3<br><br><br> 6x + 8<br><br> 8x + 9<br><br> 8x + 5<br><br> 5x + 8
beks73 [17]

\\ \sf\longmapsto 5x+3(x+2)+3

\\ \sf\longmapsto 5x+3x+6+3

\\ \sf\longmapsto (5+3)x+9

\\ \sf\longmapsto 8x+9

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3 years ago
What is the area of the shaded region?
jolli1 [7]

Hello!

<h2>Answer:</h2><h2 />

\boxed{ \bf The~area~of~the~shaded~region~is~B.~24 mm^2}

______________________________________________________

<h2>Explanation:</h2>

To find the area of the shaded region, we must find the area of the inner white triangle and subtract it from the area of the outer blue one.

Outer:

A = \frac{1}{2}bh

A =  \frac{1}{2}(12 · 5)

A =  \frac{1}{2}(60)

A = 30 mm²

Inner:

A = \frac{1}{2}bh

A = \frac{1}{2}(4 · 3)

A = \frac{1}{2}(12)

A = 6

30 - 6 = 24

7 0
3 years ago
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