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2 years ago

Multiply. Write your answer as a fraction in simplest form 9/10 x 2/3

Mathematics

2 answers:

Oduvanchick [21]2 years ago

8 0

Answer:

3/5

Step-by-step explanation:

9/10 and 2/3 can cross cancel

3 goes into 9, 3 times

2 goes into 10, 5 times

they both go into themselves once

our new fractions are 3/5 and 1/1 which equals 3/5

Airida [17]2 years ago

7 0

Answer:

3/5 or 0.6

Step-by-step explanation:

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Fill in the table using this function rule. y = 10x-3 X - 0

dexar [7]

Answer:

Step-by-step explanation:

y = 10(- 1) - 3 = - 13

y = 10(0) - 3 = - 3 

y = 10(1) - 3 = 7 

y = 10(5) - 3 = 47

5 0

3 years ago

Find the value of x. Round the length to the nearest tenth.

Mamont248 [21]

From right triangle trigonometry, we have the following:

$\displaystyle{ tan(35^o)= \frac{opposite \ side }{adjacent \ side }$ ,

where the "opposite side" means the opposite side to angle with measure $35^o$ , and "adjacent side" means the adjacent side to angle with measure $35^o$ .

$tan(35^o)$ is a constant which can be found using a calculator.

In the calculator of the pc press: view - scientific - 35 - tan.

This gives $tan(35^o)=0.7$

Thus, back in the equation $\displaystyle{ tan(35^o)= \frac{opposite \ side }{adjacent \ side }$ we substitute as follows and solve:

$\displaystyle{0.7= \frac{x }{12 }\\\\$

$x=0.7\cdot12=8.4$

Answer: 8.4 cm

5 0

2 years ago

Read 2 more answers

The time to complete a standardized exam is approximately normal with a mean of 70 minutes and a standard deviation of 10 minus.

AnnyKZ [126]

Answer:

Step-by-step explanation:

Given that the time to complete a standardized exam is approximately normal with a mean of 70 minutes and a standard deviation of 10 minutes.

P(completing exam before 1 hour)

= P(less than an hour) = P(X<60)

=P(Z< $\frac{60-70}{10} =-1$ )

=0.5-0.34=0.16

i.e. 16% of students completed the standardized exam.

7 0

2 years ago

use green's theorem to evaluate the line integral along the given positively oriented curve. c 9y3 dx − 9x3 dy, c is the circle

Rina8888 [55]

The line integral along the given positively oriented curve is -216π. Using green's theorem, the required value is calculated.

<h3>What is green's theorem?</h3>

The theorem states that,

$\int_CPdx+Qdy = \int\int_D(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y})dx dy$

Where C is the curve.

<h3>Calculation:</h3>

The given line integral is

$\int_C9y^3dx-9x^3dy$

Where curve C is a circle x² + y² = 4;

Applying green's theorem,

P = 9y³; Q = -9x³

Then,

$\frac{\partial P}{\partial y} = \frac{\partial 9y^3}{\partial y} = 27y^2$

$\frac{\partial Q}{\partial x} = \frac{\partial -9x^3}{\partial x} = 27x^2$

$\int_C9y^3dx-9x^3dy = \int\int_D(-27x^2 - 27y^2)dx dy$

⇒ $-27\int\int_D(x^2 + y^2)dx dy$

Since it is given that the curve is a circle i.e., x² + y² = 2², then changing the limits as

0 ≤ r ≤ 2; and 0 ≤ θ ≤ 2π

Then the integral becomes

$-27\int\limits^{2\pi}_0\int\limits^2_0r^2. r dr d\theta$

⇒ $-27\int\limits^{2\pi}_0\int\limits^2_0 r^3dr d\theta$

⇒ $-27\int\limits^{2\pi}_0 (r^4/4)|_0^2 d\theta$

⇒ $-27\int\limits^{2\pi}_0 (16/4) d\theta$

⇒ $-108\int\limits^{2\pi}_0 d\theta$

⇒ $-108[2\pi - 0]$

⇒ -216π

Therefore, the required value is -216π.

Learn more about green's theorem here:

brainly.com/question/23265902

#SPJ4

3 0

1 year ago

Mrs. Torchia picked 54 flowers, which represents 60% of all the flowers in her garden.How many flowers are left in Mrs. Torchia’

sweet-ann [11.9K]

Find a percent of a quantity as a rate per 100 (e.g., 30% of a quantity means 30/100 times the quantity); solve problems involving finding the whole given a part and the percent.

5 0

2 years ago