Answer:
Theres a lot going on in this question but i tried my best to answer it all, correctly. Sorry if something is wrong or i misread the question. check explanation for answer.
Step-by-step explanation:
I'm not sure to use pi or 3.14 so i just did both.
Circle A's radius = 5cm
Circle B's radius = 10cm
Circle C's radius = 13cm
Circle D's = 12cm
(circle A)
π = 3.14
A = πr²
A = 3.14(5²)
A = 3.14(25)
A = 78.5cm²
π = π
A = πr²
A = π(5²)
A = π(25)
A = 78.54cm²
(circle B)
π = 3.14
A = πr²
A = 3.14(10²)
A = 3.14(100)
A = 314cm²
π = π
A = πr²
A = π(10²)
A = π(100)
A = 314.16cm²
(circle C)
π = 3.14
A = πr²
A = 3.14(13²)
A = 3.14(169)
A = 530.7cm²
π = π
A = π(13²)
A = π(169)
A = 530.9cm²
(circle D)
π = 3.14
A = πr²
A = 3.14(12²)
A = 3.14(144)
A = 452.2cm²
π = π
A = πr²
A = π(12²)
A = π(144)
A = 452.4cm²
452.2 / 78.5 =5.8
circle d is 5( almost 6) times greater than circle A
The answer is D , I promise
Answer:
Step-by-step explanation:
A complex number is defined as z = a + bi. Since the complex number also represents right triangle whenever forms a vector at (a,b). Hence, a = rcosθ and b = rsinθ where r is radius (sometimes is written as <em>|z|).</em>
Substitute a = rcosθ and b = rsinθ in which the equation be z = rcosθ + irsinθ.
Factor r-term and we finally have z = r(cosθ + isinθ). How fortunately, the polar coordinate is defined as (r, θ) coordinate and therefore we can say that r = 4 and θ = -π/4. Substitute the values in the equation.
Evaluate the values. Keep in mind that both cos(-π/4) is cos(-45°) which is √2/2 and sin(-π/4) is sin(-45°) which is -√2/2 as accorded to unit circle.
Hence, the complex number that has polar coordinate of (4,-45°) is
Answer:
Step-by-step explanation:
Given that
A right triangle has side lengths a, b, and c
Because you did not attached photo of the right triangle so I will assume that:
- Side a is the adjacent (A)
- Side b is the opposite (O)
- Side c is the hypotenuse (H)
(Please have a look at the attached photo)
To solve for the trigonometric functions of x, we need to recall the ratios they represent as shown below.
EX: the sine of x is equal to the side opposite of angle x over the hypotenuse. Hence, we have the expressions of the trigonometric functions as shown below:
Hope it will find you well