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Masja [62]
3 years ago
15

What is the percent of aluminum in al2(so4)3

Chemistry
2 answers:
Lena [83]3 years ago
7 0

Answer : The percent of aluminium in Al_2(SO_4)_3 is 15.77\%

Solution :

Molar mass of Aluminium = 26.98 g/mole

Molar mass of Al_2(SO_4)_3 = 342.15 g/mole

First we have to calculate the mass of Aluminium.

Mass of 2 Al atoms = 2 × 26.98 g/mole = 53.96 g/mole

Now we have to calculate the percent composition of Aluminium in Al_2(SO_4)_3

\%\text{ of Al}=\frac{\text{ Mass of Al}}{\text{ Total mass}}\times 100

Now put all the given values in this formula, we get

\%\text{ of Al}=\frac{53.96g/mole}{342.15g/mole}\times 100

\%\text{ of Al}=15.77\%

Therefore, the percent of aluminium in Al_2(SO_4)_3 is 15.77\%

Mashutka [201]3 years ago
6 0

Answer should be: 15.77% or round to 15.80% / 15.8%

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The molar concentration of sucrose in a can of soda is 0.375 M. How much sucrose would be found in a 2 liter bottle of soda of t
antoniya [11.8K]

Answer:

C)  0.75 mol.

Explanation:

  • Molarity is defined as the no. of moles of solute dissolved in 1.0 L of the solution.

So, The molar concentration of sucrose in a can of soda is 0.375 M means that: every 1.0 L of sucrose contains 0.375 mol of sucrose.

∴ 2 liter bottle of soda of the same concentration contains (2 * 0.375 mol = 0.75 mol) of sucrose.

<em>Thus, the right choice is: C)  0.75 mol.</em>

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3 years ago
Based on the kinetic molecular theory (KMT), which statement is true?
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5 0
3 years ago
Identify the products and the reactants in the following chemical equations
liq [111]

Answer:

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6 0
2 years ago
Formula los siguientes compuesto: Dietil eter, Etanol, Propanotriol, Acido Propanodioico, Pentanal, Pentano-2,4-diona, Metanoato
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Answer:

Explanation:

En este caso para formular los compuestos, debes identificar el grupo funcional principal de la molecula. Una vez que eso está hecho, puedes intentar formularlo.

Empezaremos primero identificando el grupo funcional principal de la molécula, para luego formularlo correctamente.

Dietil eter: la terminación eter al final significa que pertenece al grupo de los éteres, el cual tiene como formula general R - O - R.

Etanol: debido a que termina en ol, este grupo pertenece a los alcoholes. Para formularlo solo se dibuja la molecula del etano, junto a un enlace con el grupo OH, como su formula general R - OH.

Propanotriol: igualmente termina en ol, por lo tanto es un alcohol, sin embargo, en este caso, tambien tiene la terminación prefija tri, asi que significa que hay 3 grupos OH en la molecula.

Acido propanodioico: esta es sencilla, porque empieza como acido, y solo hay un grupo funcional que empieza así y son los acidos carboxilicos, es decir, el grupo COOH (R - COOH) que es el carboxilo. Tiene el prefijo di, antes del oico, por lo que son dos carboxilos presentes en la molecula.

Pentanal: el sufijo al, significa que pertenece al grupo de los aldehidos, en este caso, posee el grupo carbonilo H - C = O.

Pentano - 2,4 - diona: la terminación ona significa que pertenece al grupo de las cetonas, (R - CO - R), parecido a los aldehidos, con la diferencia de que tiene grupos alquilos en lugar de un hidrogeno.

Metanoato de metilo: la terminación ato de ilo, pertenece a los esteres, (R - COOR) derivado de los acidos carboxilicos.

De aqui en adelante solo mencionaré los grupos funcionales pues ya se explicó el por que, por sus terminaciones:

Ciclohexano - 1.3 - diol: este pertenece a los alcoholes.

Acido heptanoico: acido carboxilico

Ciclobutil metil eter: eteres

Acetato de etilo: ester

2-metilbenzaldehído: aldehído unido a un grupo aromatico como el benceno.

Ciclohexanona: un ciclo (cadena cerrada) unido a un grupo carbonilo.

Butanona: cetona.

Observa la foto adjunta para que veas la formulación de cada una:

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