a. 381.27 m/s
b. the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triiodide
<h3>Further explanation</h3>
Given
T = 100 + 273 = 373 K
Required
a. the gas speedi
b. The rate of effusion comparison
Solution
a.
Average velocities of gases can be expressed as root-mean-square averages. (V rms)
R = gas constant, T = temperature, Mm = molar mass of the gas particles
From the question
R = 8,314 J / mol K
T = temperature
Mm = molar mass, kg / mol
Molar mass of Sulfur dioxide = 64 g/mol = 0.064 kg/mol
b. the effusion rates of two gases = the square root of the inverse of their molar masses:
M₁ = molar mass sulfur dioxide = 64
M₂ = molar mass nitrogen triodide = 395
the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triodide
Answer:
8.60 * 
atoms N2
Explanation:
We want to convert grams to moles and then moles to atoms.
First, we convert grams of nitrogen gas (which is N2) to moles. To do so, we need the molar mass of N2, which is just 14.01 * 2 = 28.02 g.
40 g N2 * 
= 1.43 mol N2
Now, we need to convert moles to atoms by using Avogadro's number, which is 
:
1.43 mol N2 * 
= 8.60 * atoms N2
Thus, the answer is 8.60 * atoms N2.
One of the major events is Volcanos etc...
Answer:
the sun im not 100% sure but yes
In the given compound, 0.2 mole of C₂H₆O will contain 1.2 moles of hydrogen.
<h3>chemical compound</h3>
In the balanced chemical compound C₂H₆O, we can deduce the following;
1 mole of C₂H₆O contains 6 moles of hydrogen
0.2 mole of C₂H₆O = ?
= 0.2 x 6 moles = 1.2 moles of hydrogen
Thus, in the given compound, 0.2 mole of C₂H₆O will contain 1.2 moles of hydrogen.
Learn more about number of moles here: brainly.com/question/15356425
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