Answer:
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Aluminum oxide produced : = 79.152 g
<h3>Further explanation</h3>
Given
46.5g of Al
165.37g of MnO
Required
Aluminum oxide produced
Solution
Reaction
2 Al (s) + 3 MnO (s) → 3 Mn (s) + Al₂O₃ (s)
mol = mass : Ar
mol = 46.5 : 27
mol = 1.722
mol = 165.37 : 71
mol = 2.329
mol : coefficient ratio Al : MnO = 1.722/2 : 2.329/3 = 0.861 : 0.776
MnO as a limiting reactant(smaller ratio)
So mol Al₂O₃ based on MnO as a limiting reactant
From equation , mol Al₂O₃ :
= 1/3 x mol MnO
= 1/3 x 2.329
= 0.776
Mass Al₂O₃ (MW=102 g/mol) :
= 0.776 x 102
= 79.152 g
When a substance changes into a different substance, you are observing its chemical properties.
In a physical change, the substance must <em>not </em>change into a different substance.
The physical and chemical properties of a substance do <em>not</em> change.
Answer:
19.29 g.cm⁻³
Solution:
Data Given:
Mass = 301 g
Volume = 15.6 cm³
Formula Used:
Density = Mass ÷ Volume
Putting values,
Density = 301 g ÷ 15.6 cm³
Density = 19.29 g.cm⁻³
Answer:
pure water, pH = 7.0 (Neutral)
lake water, pH = 6.5 (Acidic)
baking soda solution, pH = 9 (Alkaline)
soapy water, pH = 12 (Alkaline)
Explanation:
The degree of acidicity or alkalinity of a solution can be determined on a pH meter. A pH below 7 is acidic; a pH of 7 is neutral; a pH value of above 7 is alkaline.
