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Svetlanka [38]
3 years ago
7

Students were asked to place a mint in their mouths and determine how long it took for the mint to dissolve. The condition of th

e mint varied in each student group. One group of students were asked to leave a whole mint in their mouth, not moving it around, and let it dissolve. Another group swirled a mint, while the other groups used mints broken into smaller pieces. See the chart for all of the manipulated variable. After reviewing that data table, what kind of result would you predict for the swirled, whole mint?
Physics
2 answers:
Llana [10]3 years ago
7 0

Students were asked to place a mint in their mouths and determine how long it took for the mint to dissolve. The condition of the mint varied in each student group. One group of students were asked to leave a whole mint in their mouth, not moving it around, and let it dissolve. Another group swirled a mint, while the other groups used mints broken into smaller pieces. See the chart for all of the manipulated variable. After reviewing that data table, what kind of result would you predict for the swirled, whole mint?


A) The time is likely between 10-30 seconds.  

B) The time is likely between 40-80 seconds.  

C) The time is likely between 90-160 seconds.  

D)    The time is likely between 100-200 seconds.

 

            ANSWER: B) The time is likely between 40-80 seconds.


  EXPLANATION:The time is likely between 40-80 seconds.

By swirling the mint, this is agitating and creating a higher frequency of collisions between the saliva particles and mint particles, increasing the rate of dissolution. Therefore, the time is likely to be less than the mint cut in half but probably more than the mint when it is in small pieces.

AnnZ [28]3 years ago
7 0

Answer: B

Explanation: The answer is B.

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2 years ago
Which statement about two objects having the same momentum is true?
Reil [10]

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The product of mass X velocity is the same for both

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7 0
3 years ago
A uniform plank of mass 10kg and length 10m rests on two supports, A and B as shown. A boy of weight 500N stands at a distance o
kifflom [539]

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U² = 142.86 N

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Explanation:

Taking summation of the moment about point A, we get the following equilibrium equation: (taking clockwise direction as positive)

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Therefore,

(500\ N)(2\ m)-(U^2)(7\ m)=0\\U^2=\frac{1000\ Nm}{7\ m}\\

<u>U² = 142.86 N</u>

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