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Korolek [52]
1 year ago
15

After travelling 4.0 km, the train reaches its maximum speed. it continues at this constant speed on the next section of the tra

ck where the track follows a curve which is part of a circle.
state the direction of the resultant force on the train as it follows the curved path.
Physics
1 answer:
lozanna [386]1 year ago
5 0

Answer:

  toward the center of the circular curve

Explanation:

An object will follow a circular path at constant speed if and only if its net acceleration is constant and directed toward the center of the curved path.

__

The result force is directed toward the center of the circle.

_____

<em>Additional comment</em>

If any part of the result force is in the direction of motion, the speed will not be constant. If the center-directed force is not constant, the path will not be circular.

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Answer:

Work done by external force is given as

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Explanation:

As per work energy Theorem we can say that work done by all force on the car is equal to change in kinetic energy of the car

so we will have

Work_{external} + Work_{gravity} + Work_{friction} = \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2

now we have

W_{gravity} = -mg(Lsin\theta)

W_{friction} = -\mu mgcos(\theta) L

so from above equation

Work_{external} - mgLsin\theta - \mu mgLcos(\theta) = \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2

so from above equation work done by external force is given as

Work_{external} = mgLsin\theta + \mu mgLcos(\theta) + \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2

8 0
3 years ago
All scientific inquiry is done using the ______________ method.
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Answer:

The scientific method

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Ask a question.

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Explanation:

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By re-arranging the equation and substituting the numbers in, we find:

p=\frac{nRT}{V}=\frac{(0.55 mol)(0.0821 Latm/Kmol)(305 K)}{8.5 L}=1.62 atm

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