Sorry, but I cannot understand the first part of this question
Nor the second part it's not finished.
<h2>please change this so that i could help</h2><h2>:D</h2><h2 /><h2>From:</h2><h2>Kenny</h2>
Answer:
First, a absolute value function is something like:
y = f(x) = IxI
remember how this work:
if x ≥ 0, IxI = x
if x ≤ 0, IxI = -x
Notice that I0I = 0.
And the range of this function is all the possible values of y.
For example for the parent function IxI, the range will be all the positive reals and the zero.
First, if A is the value of the vertex of the absolute function, then we know that A is the maximum or the minimum value of the function.
Now, if the arms of the graph open up, then we know that A is the minimum of the function, and the range will be:
y ≥ A
Or all the real values equal to or larger than A.
if the arms of the graph open downwards, then A is the maximum of the function, and we have that the range is:
y ≤ A
Or "All the real values equal to or smaller than A"
Minor Arc AC = 110 degrees (given)
As indicated in the hints,
OA=OC => OAC=OCA=(180-110)/2 = 35
Similarly,
OAB=OBA=(48-35)=13
=>
OBC=OCB=(180-35-35-13-13)/2=(180-96)/2=84/2=42
=>
Angle B = 13+42 = 55 degrees
Check:
55+55+35+35+13+13 = 180 degrees (angles of a triangle) ok.
x⁸ + 48x⁷ + 1008x⁶ + 12096x⁵ + 90720x⁴ + 435456x³ + 1306368x² + 2239488x + 1679616
<u>Explanation:</u>
We know
(x+y)ⁿ = ∑ ⁿCₐxⁿ⁻ᵃyᵃ
and ⁿCₐ = n! / ( a! ) . ( n-a )!
So,
(x+6)⁸ = ⁸C₀x⁸ + ⁸C₁(x)⁸⁻¹(6)¹ + ⁸C₂(x)⁸⁻²(6)² + ⁸C₃(x)⁸⁻³(6)³ + .......+ ⁸C₈(x)⁸⁻⁸(6)⁸
= ₓ⁸ + 8x⁷ₓ 6 + 28x⁶ₓ 36 + 56x⁵ₓ 216 + 70x⁴ₓ 1296 + 56x³ₓ 7776 + 28x²ₓ 46656 + 8x . 279936 + 1679616
= x⁸ + 48x⁷ + 1008x⁶ + 12096x⁵ + 90720x⁴ + 435456x³ + 1306368x² + 2239488x + 1679616
Thus, the expansion of ( x+6)⁸ using binomial theorm is
x⁸ + 48x⁷ + 1008x⁶ + 12096x⁵ + 90720x⁴ + 435456x³ + 1306368x² + 2239488x + 1679616
R equals approximately 4/5
