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tiny-mole [99]
3 years ago
12

What are beats? Physics B

Physics
1 answer:
ivanzaharov [21]3 years ago
3 0

Beats are a garden plant with thick leaves and a rounded red root.  

The rounded red root of the plant is eaten as a vegetable.

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A purse at radius 2.30 m and a wallet at radius 3.45 m travel in uniform circular motion on the floor of a merry-go-round as the
ivolga24 [154]

Answer:

The acceleration of the wallet is 3\hat{i}+6\hat{j}

Explanation:

Given that,

Radius of purse r= 2.30 m

Radius of wallet r'= 3.45 m

Acceleration of the purse a=2\hat{i}+4.00\hat{j}

We need to calculate the acceleration of the wallet

Using formula of acceleration

a=r\omega^2

Both the purse and wallet have same angular velocity

\omega=\omega'

\sqrt{\dfrac{a}{r}}=\sqrt{\dfrac{a'}{r'}}

\dfrac{a}{r}=\dfrac{a'}{r'}

\dfrac{a'}{a}=\dfrac{r'}{r}

\dfrac{a'}{a}=\dfrac{3.45}{2.30}

\dfrac{a'}{a}=\dfrac{3}{2}

a'=\dfrac{3}{2}\times(2\hat{i}+4.00\hat{j})

a'=3\hat{i}+6\hat{j}

Hence, The acceleration of the wallet is 3\hat{i}+6\hat{j}

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A spaceship is moving past Earth at 0.99c. The spaceship fires two lasers. Laser A is in the same direction it is traveling, and
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Answer:

Vx' = (Vx - u) / (1 - Vx *u / c^2)      velocity transformation formula

In both cases we wish to measure the velocity in the frame of the earth which is moving at speed u = -.99 c relative to the spaceship

VA' = (c + .99c) / (1 - (-.99 c * c) / c^2) = 1.99c / 1.99 = c

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In both cases an observer on earth will observe the light traveling at speed c.

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A pendulum is constructed from a 7.58 kg bowling ball hanging on a 3.00m long rope. The ball is pulled back until the vertical h
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