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g100num [7]
3 years ago
12

Calculate specific heat of liquid if a 450. g iron block is heated to 98.0 C and then droped into a calorimeter with 125 g of un

known liqid at 19.8 C. After 2 minutes the temp inside the calorimeter rise to a maximum of 40.4 C.
Physics
1 answer:
Naya [18.7K]3 years ago
7 0

Answer:

Specific heat of liquid 1.258 \ J/g^0C.

Explanation:

We know in thermal equilibrium :

Loss in heat by iron block = Gain in heat by liquid .

Specific heat of iron = 0.45 J/g^0C.  { source internet }

Now , loss in heat by iron block = mC_{iron}\Delta T=450\times 0.45\times 57.6=11664\ J.

Heat gain by liquid=mC_{liquid}\Delta T=450\times C_{liquid}\times 20.6=9270\times C_{liquid}.

Equating both we get :

C_{liquid}=1.258 \ J/g^0C.

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