_PCi5 + _H20 + _H3PO4 _HCI<br>
A.) 1,3,1,5<br>
B.) 2,4,1,5<br>
C.) 1,4,1,5<br>
D.) 2,1,2,5
Ann [662]
Answer:
C
Explanation:
because of the kids are doing well and staying in the middle of the day early to get a new phone number for home now deep
Answer:
.98m
Explanation:
Vf=Vi+2at
(V F)^2+2 ( change in distance )
X f= i ( change in V & T )
EK=1/2Mv^2,EG=mgh
This is False. Newton's First Law of Motion is often called the law of inertia.
Answer:
Work done by the force of friction is 305.96 joules.
Explanation:
It is given that,
Mass of the child, m = 21 kg
Height of the slide, h = 1.5 m
Speed of the child at the bottom, v = 0.51 m/s
Let W is the work done by the force of friction on the child. It can be calculated using the work energy theorem as :
W = -305.96 joules
So, the work done by the force of friction on the child is 305.96 joules. Hence, this is the required solution.
Answer:
0.00264C
Explanation:
Using the Columbs law formula
F = kq1q2/r²
F is the force of attraction
q1 and q2 are the charges
r is the distance between the charges.
k is the Coulomb's cinsrsnty
Given F = 19N, q1 = -0.0005C
r = 25m q2 = ?
Substituting
19 = 9×10^9×-0.0005q2/25²
11875 = -4,500,000q2
q2 = 11,875/-4,500,000
q2 = - 0.0264C
Magnitude of the second charge is 0.00264C