Answer:
α = 13.7 rad / s²
Explanation:
Let's use Newton's second law for rotational motion
∑ τ = I α
we will assume that the counterclockwise turns are positive
F₁ 0 + F₂ R₂ - F₃ R₃ = I α
give us the cylinder moment of inertia
I = ½ M R₂²
α = (F₂ R₂ - F₃ R₃)
let's calculate
α = (24 0.22 - 13 0.10) 2/12 0.22²
α = 13.7 rad / s²
Answer:
The value is
Explanation:
From the question we are told that
The mass of the car is
The acceleration is
Generally the net force applied on the rope is mathematically represented as
Here W is the weight of the car which is evaluated as
=>
=>
Generally the net force can also be mathematically represented as
So
=>
=>