When a satellite is moving around the Earth's orbit, two equal forces are acting on it. The centripetal and the centrifugal force. The centripetal force is the force that attracts the object toward the center of the axis of rotation. The opposite force is the centrifugal force. It draws the object away from the center. When these forces are equal, the satellite uniformly rotates along the orbit.
Centripetal force = Centrifugal force
Mass of satellite * centripetal acceleration = Mass of satellite * centrifugal acceleration
Centripetal acceleration = Centrifugal acceleration

ω^2r
where

= mass of earth
G = gravitational constant = 6.6742 x 10-11<span> m</span>3<span> s</span>-2<span> kg</span><span>-1
</span>

= radius of earth
ω = angular velocity
<span>r = radius of orbit
To convert to angular velocity:
</span>Tangential velocity = rω
ω = 5000/r
Then,

r = 2557110.465 m
Therefore, the distance of the centers of the earth and the satellite is
2.6 x 10^6 m.
<span>
</span>
Answer:
m₂ = 3kg
Explanation:
The question wasn't clear about what direction the initial velocity of the second cart was, so I'll assume it was going left at 2.0m/s.
Anyway, this is a conservation of momentum problem. The equation you need to use is the one written in blue. They want you to solve for the mass of the second cart, so do some algebra and rearrange that blue equation in term of m₂.
Now that you have the equation for m₂, plug in all the values given from the question and you'll get 3kg.
Potential energy is the energy possessed by a body at rest while the kinetic energy is the energy possessed by a body in motion.
Potential energy is given by mass× gravitational acceleration × height
That is energy = mgh
For the first ball the potential energy is 2.268 ×10 ×5 = 113.4 J (5 lb = 2.268 kg)
The second ball with the same mass will have 2.268 ×10 ×10 = 226.8 J
Thus, the potential energy is dependent on the height of a given body and therefore the ball at the 5 foot hill has less potential energy.
Answer:
120 m
Explanation:
We can calculate the period of a pendulum using the following expression.

where,
T is the period of the pendulum
L is the length of the pendulum (here it coincides with the height of the tower)
g is the gravity

Answer:
Today my mom drove the car and when the car was standing it was potential energy but when the car started moving it turned into kinetic energy. Hope it helps.
Explanation: