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maksim [4K]
3 years ago
15

True or False: TV waves have a shorter wavelength than microwave rays

Physics
2 answers:
Ksju [112]3 years ago
5 0
The answer is going to be True!
kogti [31]3 years ago
3 0

Answer:

I think true..... :))))))))))

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Which statement correctly describes the location, charge, and mass of the
Alenkinab [10]

The neutrons are inside the nucleus, have no charge, and have mass.

7 0
3 years ago
A woman can lift barrels a vertical distance of 1 meter or can roll them up a 2-meter long ramp to the same elevation. If she us
olchik [2.2K]

Answer:

answer is 1/2 as much force required

8 0
2 years ago
A solid block, with a mass of 0.15kg, on a frictionless surface is pushed directly onto a horizontal spring, with a spring const
iren [92.7K]

Answer:

16.1 m/s

Explanation:

We can solve the problem by using the law of conservation of energy.

At the beginning, the spring is compressed by x = 35 cm = 0.35 m, and it stores an elastic potential energy given by

U=\frac{1}{2}kx^2

where k = 316 N/m is the spring constant. Once the block is released, the spring returns to its natural length and all its elastic potential energy is converted into kinetic energy of the block (which starts moving). This kinetic energy is equal to

K=\frac{1}{2}mv^2

where m = 0.15 kg is the mass of the block and v is its speed.

Since the energy must be conserved, we can equate the initial elastic energy of the spring to the final kinetic energy of the block, and from the equation we obtain we can find the speed of the block:

\frac{1}{2}kx^2=\frac{1}{2}mv^2\\v=\sqrt{\frac{kx^2}{m}}=\sqrt{\frac{(316 N/m)(0.35 m)^2}{0.15 kg}}=16.1 m/s

4 0
3 years ago
A concave mirror with a focal length of 32 cm produces an image whose distance from the mirror is one-third the object distance.
iVinArrow [24]

Answer:

part A ⇒ u = 1.28 m

part B ⇒v = 0.43 m

Explanation:

for u is the distance to the object from the mirror and v is the distance from the mirror to the image.

Part A:

the mirror equation is given by:

1/f = 1/v + 1/u

but we told that, v = 1/3u:

1/f = 3/v + 1/u = 4/u

1/f = 4/u

  f = u/4

 u = 4f

    = 4×(32×10^-2)

    = 1.28 m

Therefore the distance from the mirror to the object is 1.28 m.  

part B:

v = 1/3×u = 1/3×(1.28) = 0.43 m

5 0
3 years ago
6. A 0.09 kg arrow hits a target at 22 m/s and penetrates 4 cm before stopping.
tatyana61 [14]
A ) v = v o - a t
0 = 22 - a · t
a · t = 22
d = v o · t - a t²/2
0.04 = 22 t - 22 t / 2
0.04 = 11 t
t = 0.04 : 11 = 0.003636 s
a = 22 / t
a = 6050 m/s²
F = m · a = 0.09 kg · 6050 m/s²
F ( target→arrow) = - 544.5 N
b ) F ( arrow→target ) = 544.5 N
c )  If the speed was doubled:  v = 44 m/s;
F = a m
a = 6050 m/s²
a · t = 44
t = 6050 : 0.04
t = 0.007272 s
d = 44 t - 44 t/2 = 22 t
d = 22 · 0.007272
d = 0.16 m = 16 cm
8 0
3 years ago
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