Each of two identical objects carries a net charge. The objects are made from conducting material. One object is attracted to a
positively charged ebonite rod, and the other is repelled by the rod. After the objects are touched together, it is found that they are each attracted by the rod. What can be concluded about the initial charges on the objects
Initially one object is positive and one is negative , with the positive charge having a greater magnitude than the negative charge.
Explanation:
The object that is attracted to a positively charged ebonite rod, must have the negative charge as the oppose charges attract. However the object that is repelled by the rod must have the positive charge because the same charges repel that's why object move away from the rod.
Now after the objects are touched together, then there must be a flow of charge from one object to other until they got the equal charge in magnitude. As the both objects repel the rod it means both have now got the positive charge. So there must be initially a positive charge wih higher magnitude.
So we can conclude that,
" Initially one object is positive and one is negative , with the positive charge having a greater magnitude than the negative charge."
The velocity of the ball when it reaches the ground is equal to B. 68.6 m/s. This value was obtained from the formula Vf = Vi + at. Vf is the final velocity. Vi is the initial velocity. The acceleration is "a", while the time of travel is "t". The solution is:
<span>Vf = Vi + at </span>Vf = 0 + (-9.8 m/s^2) (7 s) Vf = -68.6 m/s
The negative sign denotes the direction of the ball.