A. The area of the paralelogram is base • height so is (4x-2)•(2x-1)= 8x^2. -8x+2
b. X=2
A= 8•4-8•2+2= 32-16+2= 14 in^2
Answer: figures C and D.
Explanation:
The question is which two figures have the same volume. Hence, you have to calculate the volumes of each figure until you find the two with the same volume.
1) Figure A. It is a slant cone.
Dimensions:
- slant height, l = 6 cm
- height, h: 5 cm
- base area, b: 20 cm²
The volume of a slant cone is the same as the volume of a regular cone if the height and radius of both cones are the same.
Formula: V = (1/3)(base area)(height) = (1/3)b·h
Calculations:
- V = (1/3)×20cm²×5cm = 100/3 cm³
2. Figure B. It is a right cylinder
Dimensions:
- base area, b: 20 cm²
- height, h: 6 cm
Formula: V = (base area)(height) = b·h
Calculations:
- V = 20 cm²· 6cm = 120 cm³
3. Figure C. It is a slant cylinder.
Dimensions:
- base area, b: 20 cm²
- slant height, l: 6 cm
- height, h: 5 cm
The volume of a slant cylinder is the same as the volume of a regular cylinder if the height and radius of both cylinders are the same.
Formula: V = (base area)(height) = b·h
Calculations:
- V = 20cm² · 5cm = 100 cm³
4. Fiigure D. It is a rectangular pyramid.
Dimensions:
- length, l: 6cm
- base area, b: 20 cm²
- height, h: 5 cm
Formula: V = (base area) (height) = b·h
Calculations:
- V = 20 cm² · 5 cm = 100 cm³
→ Now, you have found the two figures with the same volume: figure C and figure D. ←
First substitute
(3)(4)/4
then simplify.
12/4
then solve
3
48-10=x x=38
38x2= 76
so basically his weight is 48, which is ten more than his fathers weight, so you subtract ten from 48, giving you 38. 38 is only half the father's weight, so you double it and get 76.
Answer:
6 X 7= 42
Step-by-step explanation:
to find the area of anything its length times width times height (LXWXH)
since they arent giving a width here its only LXH=?
so 6X7=42