Question

The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 ounces with a sample standard deviation of 0.5 ounces. At the 0.05 level of​ significance, perform a hypothesis test to see if the true mean weight is < 4 ounces. What is the correct conclusion at the 0.05 level of​ significance?

Answer 1

Answer:

Step-by-step explanation:

Mean weigth is 3.8

standard deviation 15 =0.5

sd2 =15*(sd₁₅ )²

sd=(15*0.25)^0.5

sd=1.94

z=(3.8-4)/((0.5)/15^0.5)

z=-1.55

p=0.060571

0.060571>.05

true mean weight is less than 4 ounces

test statistic= (sample mean-mean)/((sd of sample)/n^0.5)

test statistic=(3.8-4)/((0.5)/15^0.5)

test statistic=-1.55