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Sveta_85 [38]
3 years ago
12

You flip a fair coin.

Mathematics
1 answer:
AURORKA [14]3 years ago
8 0
What are the answer choices.
You might be interested in
What is 720° converted to radians? <br> a) 1/4<br> b) pi/4<br> c) 4/pi<br> d) 4pi
baherus [9]

4π radians

<h3>Further explanation</h3>

We provide an angle of 720° that will be instantly converted to radians.

Recognize these:

  • \boxed{ \ 1 \ revolution = 360 \ degrees = 2 \pi \ radians \ }
  • \boxed{ \ 0.5 \ revolutions = 180 \ degrees = \pi \ radians \ }

From the conversion previous we can produce the formula as follows:

  • \boxed{\boxed{ \ Radians = degrees \times \bigg( \frac{\pi }{180^0} \bigg) \ }}
  • \boxed{\boxed{ \ Degrees = radians \times \bigg( \frac{180^0}{\pi } \bigg) \ }}

We can state the following:

  • Degrees to radians, multiply by \frac{\pi }{180^0}
  • Radians to degrees, multiply by \frac{180^0}{\pi }

Given α = 720°. Let us convert this degree to radians.

\boxed{ \ \alpha = 720^0 \times \frac{\pi }{180^0} \ }

720° and 180° crossed out. They can be divided by 180°.

\boxed{ \ \alpha = 4 \times \pi \ }

Hence, \boxed{\boxed{ \ 720^0 = 4 \pi \ radians \ }}

- - - - - - -

<u>Another example:</u>

Convert \boxed{ \ \frac{4}{3} \pi \ radians \ } to degrees.

\alpha = \frac{4}{3} \pi \ radians \rightarrow \alpha = \frac{4}{3} \pi \times \frac{180^0}{\pi }

180° and 3 crossed out. Likewise with π.

Thus, \boxed{\boxed{ \ \frac{4}{3} \pi \ radians = 240^0 \ }}

<h3>Learn more  </h3>
  1. A triangle is rotated 90° about the origin brainly.com/question/2992432  
  2. The coordinates of the image of the point B after the triangle ABC is rotated 270° about the origin brainly.com/question/7437053  
  3. What is 270° converted to radians? brainly.com/question/3161884

Keywords: 720° converted to radians, degrees, quadrant, 4π, conversion, multiply by, pi, 180°, revolutions, the formula

6 0
3 years ago
Read 2 more answers
A curve is describe by the following parametric equations:
soldi70 [24.7K]

Answer:

A. The curve is a parabola with a vertex at (3,-4) and is traced from left to right for increasing values of t.

Step-by-step explanation:

x = 3 + t

y = t² − 4

Eliminating the parameter:

t = x − 3

y = (x − 3)² − 4

This is an upwards parabola with a vertex at (3, -4).

x = 3 + t, so as t increases, x increases.

So the curve is traced from left to right.

7 0
3 years ago
Determine which equations have the same solution set as StartFraction 2 Over 3 EndFraction minus x plus StartFraction 1 Over 6 E
Lina20 [59]

Answer:

A, B, F

Step-by-step explanation:

2/3 - x + 1/6 = 6x

Collect like terms

2/3 + 1/6 = 6x + x

(4+1) / 6 = 7x

5/6 = 7x

x = 5/6 ÷ 7

= 5/6 × 1/7

x = 5/42

a) 4 - 6x + 1 = 36x

4 + 1 = 36x + 6x

5 = 42x

x = 5/42

Equivalent to the last step of the simplification above

b) 5/6 - x = 6x

5/6 = 6x + x

5/6 = 7x

This is equivalent to the third step of the simplification

c) 4 - x + 1 = 6x

4 + 1 = 6x + x

5 = 7x

x = 5/7

Not equivalent to any of the steps in the simplification above

d) 5/6 + x = 6x

5/6 = 6x - x

5/6 = 5x

x = 5/6 ÷ 5

= 5/6 × 1/5

x = 5/30

Not equivalent to any of the steps in the simplification above

e) 5 = 30x

x = 5/30

Not equivalent to any of the steps in the simplification above

f) 5 = 42x

x = 5/42

Equivalent to the last step of the simplification above

4 0
3 years ago
Can we obtain a diagonal matrix by multiplying two non-diagonal matrices? give an example
polet [3.4K]
Yes, we can obtain a diagonal matrix by multiplying two non diagonal matrix.

Consider the matrix multiplication below

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]   \left[\begin{array}{cc}e&f\\g&h\end{array}\right] =  \left[\begin{array}{cc}a e+b g&a f+b h\\c e+d g&c f+d h\end{array}\right]

For the product to be a diagonal matrix,

a f + b h = 0 ⇒ a f = -b h
and c e + d g = 0 ⇒ c e = -d g

Consider the following sets of values

a=1, \ \ b=2, \ \ c=3, \ \ d = 4, \ \ e=\frac{1}{3}, \ \ f=-1, \ \ g=-\frac{1}{4}, \ \ h=\frac{1}{2}

The the matrix product becomes:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}\frac{1}{3}&-1\\-\frac{1}{4}&\frac{1}{2}\end{array}\right] = \left[\begin{array}{cc}\frac{1}{3}-\frac{1}{2}&-1+1\\1-1&-3+2\end{array}\right]= \left[\begin{array}{cc}-\frac{1}{6}&0\\0&-1\end{array}\right]

Thus, as can be seen we can obtain a diagonal matrix that is a product of non diagonal matrices.
8 0
3 years ago
Read 2 more answers
Solve for x: 1 &lt; x + 3 &lt; 4
Mnenie [13.5K]

Answer:

-2<x<1

Step-by-step explanation:

That's all it can go I think.

6 0
3 years ago
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