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3 years ago

Section 1: Write the following times in 24-hour clock time:

Mathematics

2 answers:

Sav [38]3 years ago

7 0

Answer:

Section 1:

a) 7:15 a.m - 19:15

b) 1:05 am - 01:05

c) 2:01 p.m - 14:01

d) 9:22 p.m - 21:22

e) 12:25 am- 24:25

Section 2:

a) 1155 hours - 11:55am

b) 1005 hours -10:05am

c) 1714 hours - 5:14pm

d) 0756 hours - 7:56am

e) 1345 hours- 1:45pm

geniusboy [140]3 years ago

4 0

Answer:

12:25 am= 00:25

Step-by-step explanation:

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What is the largest possible integral value in the domain of the real-valued function

kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

Algebra I

Domain is the set of x-values that can be inputted into function f(x)

Calculus

Antiderivatives
Integral Property: $\int {cf(x)} \, dx = c\int {f(x)} \, dx$
Integration Method: U-Substitution
[Integration] Reverse Power Rule: $\int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C$

Step-by-step explanation:

Step 1: Define

$f(x) = \frac{1}{\sqrt{800-2x} }$

Step 2: Identify Variables

Using U-Substitution, we set variables in order to integrate.

$u = 800-2x\\du = -2dx$

Step 3: Integrate

Define: $\int {f(x)} \, dx$
Substitute: $\int {\frac{1}{\sqrt{800-2x} } } \, dx$
[Integral] Int Property: $-\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx$
[Integral] U-Sub: $-\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du$
[Integral] Rewrite: $-\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du$
[Integral - Evaluate] Reverse Power Rule: $-\frac{1}{2}(2\sqrt{u}) + C$
Simplify: $-\sqrt{u} + C$
Back-Substitute: $-\sqrt{800-2x} + C$
Factor: $-\sqrt{-2(x - 400)} + C$

Step 4: Identify Domain

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0

3 years ago

"Sketch a possible graph for a negative Quintic polynomial with one real zero." Can anyone explain how this is done? And if poss

Sidana [21]

quintic means degree of 5.

a negative quintic would be: f(x) = -x⁵ +

an example with one real zero could be: -x⁵ + x³ + x + 3 (see attachment)

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3 years ago

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Y=–3x + 6y=9 What is the solution to the system of equations? (–21, 9) (9, –21) (–1, 9) (9, –1)

weqwewe [10]

ANSWER

The solution is $(-1,9)$

EXPLANATION

We want to solve the simultaneous equations

$y=-3x+6---(1)$

and

$y=9--(2)$ .

We substitute equation (2) in to equation (1), to obtain

$9=-3x+6$

This has now become a linear equation in a single variable $x$ .

We solve for x by grouping like terms.

$9-6=-3x$

$3=-3x$

We divide through by negative 3 to get;

$-1=x$ .

Hence, the solution is $(-1,9)$

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3 years ago

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How do I do this my hwk id due tomoorw

nexus9112 [7]

The perimeter of the given circle is 25.1 square cm.

Step-by-step explanation:

From the given diagram, the radius of the given circle is 4 cm.

The perimeter of any given circle is calculated by multiplying 2π with the radius. The radius of this circle is 4 cm and it says π = 3.142

The Perimeter for the given circle = 2π × r = 2 × 3.142 × 4 cm = 6.284 × 4 cm = 25.136 cm. Rounding this off to one decimal 25.136 square cm, the perimeter equals 25.1 square cm.

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3 years ago

I can't think of any right answer?

madam [21]

I think the answer is true
Hope this helps!!
Please consider brainliest!<3

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3 years ago

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