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4 years ago

Section 1: Write the following times in 24-hour clock time:

Mathematics

2 answers:

Sav [38]4 years ago

7 0

Answer:

Section 1:

a) 7:15 a.m - 19:15

b) 1:05 am - 01:05

c) 2:01 p.m - 14:01

d) 9:22 p.m - 21:22

e) 12:25 am- 24:25

Section 2:

a) 1155 hours - 11:55am

b) 1005 hours -10:05am

c) 1714 hours - 5:14pm

d) 0756 hours - 7:56am

e) 1345 hours- 1:45pm

geniusboy [140]4 years ago

4 0

Answer:

12:25 am= 00:25

Step-by-step explanation:

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An art teacher needs to 5 boxes of markrrs to complete a project with a class of 20 students. How many boxes of markers will he

sleet_krkn [62]

20students : 5 boxes

Divided by 5

4students : 1 boxes

28students : x boxes

28/4 = 7

28students : 7 boxes

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3 years ago

Please help with numbers 5-18..ik its a lol but please this a 4 page packet and please show work

galina1969 [7]

Answer:

5-18 answers below ↓

Step-by-step explanation:

5) 14/2=7

7^2=49

10^2=100

h^2+49=100

-49 -49

h^2=51 h=✓51= 3•17

6) 48/2= 24

24^2=576

44^2=1936

h^2+576=1936

-576 -576

h^2=1360 h=✓1360= 4•340

7) 24^2+b^2=32^2 (leg is short side & hypo.. is long side)

576+b^2=1024

-576 -576

b^2= 448 b=✓448=4•112 length of 3rd side it's hypo..

8) 24^2+b^2=45^2

576+b^2=2025

-576 -576

b^2=1449 b=✓1449=9•161 length of 3rd side hypo..

9) 40^2+b^2=85^2

1600+b^2=7225

-1600 -1600

b^2=5625 b^2=✓5625 b=75 length of 3rd side leg

10) 49^2+b^2=168^2

2401+b^2=28,224

-2401 -2401

b^2=25,823 b=✓25,823 b=49•527 length of 3rd side hypo..

11) 72^2+b^2=78^2

5184+b^2=6084

-5184 -5184

b^2=900 b=✓900=30 length of 3rd side leg

12) 7^2+x^2=10^2

49+x^2=100

-49 -49

x=51=3•17

13) 12^2+x^2=28^2

144+x^2=784

-144 -144

x=✓640=4•160

14) 44^2+x^2=52^2

1936+x^2=2704

-1936 -1936

x=✓768=4•192

15) 120^2+h^2=125^2

14,400+h^2=15,625

-14,400 -14,400

h^2=1,225 h=✓1225 h=35

16) might be wrong but worth a try 8+8=16

16^2+x^2=16^2

256+x^2=256 x=0 don't know these challenge ones sorry, but the rest of the questions are correct hope this helps u (:

7 0

3 years ago

Claire mowed 7 lawns last week. She mowed each lawn in 7/18 hour. She mowed the same lawns this week in 5/18 hour. How many time

Wittaler [7]

I think it’s 2 hours

7 0

3 years ago

Find an equation that passes through the points (2,4) and is perpendicular to the line 3x+4y-22=0

elena-14-01-66 [18.8K]

Hello:
the equation is : y = ax+b
the slope is a : a×(-3/4) = -1......( perpendicular to a line :

3x+4y-22=0 : another equation is : y = (-3/4)x +22/4 with the slope : (-3/4))

a =4/3

an equation is : y - 4 = (4/3)(x-2)

6 0

3 years ago

What is the function g(x) created from f(x) = x^2 by moving the graph left 9 units, vertically stretching it by a factor of 4, a

MariettaO [177]

Given:

The parent function is $f(x)=x^2$

We need to determine the function g(x) created from the function f(x) by moving the graph left 9 units, vertically stretching it by a factor of 4, and shifting the graph up 5 units.

Shift left 9 units:

The rule to shift the graph c units to the left is given by

$y=f(x+c)$

where c is the positive real number.

Hence, to shift the graph 9 units to the left is given by

$f(x)=(x+9)^2$

Vertical stretch by a factor of 4:

The rule to stretch the graph vertically by a factor of c is given by

$y=cf(x)$

where $c>1$

Hence, to stretch the graph vertically by a factor of 4, we have;

$f(x)=4(x+9)^2$

Shifting 5 units up:

The rule to shift the graph c units upward is given by

$y=f(x)+c$

where c is the positive real number.

Hence, to shift the graph 5 units upward is given by

$f(x)=4(x+9)^2+5$

Therefore, the function $g(x)=4(x+9)^2+5$ is created from the graph $f(x)=x^2$ by moving the graph left 9 units, vertically stretching it by a factor of 4 and shifting up 5 units.

Hence, the graph g(x) is $g(x)=4(x+9)^2+5$

5 0

3 years ago