Which of the following groups are like terms?

Mathematics

1 answer:

Mice21 [21]2 years ago

7 0

Answer:

We need the groups

Step-by-step explanation:

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Jimmy took out a loan for $5,600 to pay for a home repair the bank offered an interest rate of 4.75 % how much interest would sh

Serjik [45]

Answer:

$698

Step-by-step explanation:

Given that :

Principal = $5600

Rate = 4.75%

Time = 3 years

Simple interest = principal * rate * time

Simple interest = $5600 * 0.0475 * 3

simple interest = $798

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2 years ago

I need some help with this rational equation. It's supposed to = -1, but for some strange reason I keep getting x^2 +2x = -1.

Rasek [7]

This one is so easy that your brain refuses to accept it.
It's looking for a harder answer, but can't find it !

You're totally correct, as far you went.    x² + 2x does = -1

Now add ' 1 ' to each side:   x² + 2x + 1 = 0

Can you factor that quadratic ?
Can you mash it through the quadratic formula ?

Actually, it's the simplest possible perfect square.

   x² + 2x + 1 = (x + 1)²

So the solutions of   x² + 2x + 1 = 0 are both   x = -1 .

Don't say anything.
I know it's embarrassing.

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2 years ago

-300 =5x-(-8x+3) step by step

cupoosta [38]

Answer:

x= −297 /13

Step-by-step explanation:

4 0

3 years ago

Find two unit vectors orthogonal to both given vectors. i j k, 4i k

Maurinko [17]

The cross product of two vectors gives a third vector $\mathbf v$ that is orthogonal to the first two.

$\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k$

Normalize this vector by dividing it by its norm:

$\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)$

To get another vector orthogonal to the first two, you can just change the sign and use $-\mathbf v$ .

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2 years ago

Worth 10 points pls help

Olenka [21]

What subject is this

3 0

2 years ago