Answer:
<h2>OOOOOOOOOOOOOO9ONOOOOOOOOOOOO</h2>
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
Answer:
an = 4n +5
Step-by-step explanation:
First we need to find a common difference
d = a2-a1 = 13-9 = 4
The formula for an
an =a1+d(n-1)
an = 9 + 4(n-1)
Distributing
an = 9+4n-4
Combine like terms
an = 4n +5
The difference between the coat cost for Delaware vs Fairfield is $0.60
Explanation:
For Delaware: 80 × .0725 = $5.80
80+5.80= $85.80
For Fairfield: 80 × .065 = $5.20
80+5.20=$85.20
85.80-85.20=0.60
Answer:
These are correct! Nice Job!!
Step-by-step explanation: