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3 years ago

#6 Pleaze !!!! Also need this for 8th grade

Mathematics

1 answer:

Sloan [31]3 years ago

4 0

Answer:

So first we need to do 2*(-2) thats easy because anything times 2is 2x. So the first one is -2+-2 or -4. The next one is also easy because anything times 1 is x so it will be -2. Next we know that 2 minuses become positive so -1*-2 = 1*2 = 2. And same goes for the next one, they cancel out yielding 2*2 = 4

<h2><u>Answers:</u></h2><h2><u></u></h2><h2><u>-4</u></h2><h2><u>-2</u></h2><h2><u>0 (already answered)</u></h2><h2><u>2</u></h2><h2><u>4</u></h2>

<u>brainliest?</u>

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A circular bicycle reflector has a diameter of 5 cm. What is the approximate area of the reflector? Use 3.14 to approximate pi a

grandymaker [24]

Answer:

Step-by-step explanation:

Area=pi×radius^2 so if diameter is 5 then radius is half that which is 2.5. So it should be a=3.14 × 2.5^2. I hope that's right.

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4 years ago

The face of the triangular concrete panel shown has an area of 22 square meters, and its base is 3 meters longer than twice its

Elodia [21]

Answer:

The length of the base is 11 meters.

Step-by-step explanation:

The diagram of the triangle is not shown; However, the given details are enough to solve this question.

Given

<em>Shape: Triangle</em>

<em>Represent the height with h and the base with b</em>

$b = 3 + 2h$

$Area = 22$

Required

Find the length of the base

The area of a triangle is calculated as thus;

$Area = \frac{1}{2} * b * h$

Substitute 22 for Area and 3 + 2h for b

The formula becomes

$22 = \frac{1}{2} * (3 + 2h) * h$

Multiply both sides by 2

$2 * 22 = 2 * \frac{1}{2} * (3 + 2h) * h$

$44 = (3 + 2h) * h$

Open the bracket

$44 = 3 * h + 2h * h$

$44 = 3h + 2h^2$

Subtract 44 from both sides

$44 - 44 = 3h + 2h^2 - 44$

$0 = 3h + 2h^2 - 44$

Rearrange

$0 = 2h^2 +3h - 44$

$2h^2 +3h - 44 = 0$

At this point, we have a quadratic equation; which is solved as follows:

$2h^2 +3h - 44 = 0$

$2h^2 + 11h - 8h - 44 = 0$

$h(2h + 11) - 4(2h + 11) = 0$

$(h - 4)(2h + 11) = 0$

Split the above

$(h - 4) = 0\ or\ (2h + 11) = 0$

$h - 4 = 0\ or\ 2h + 11 = 0$

Solve the above linear equations separately

$h - 4 = 0$

Add 4 to both sides

$h - 4 + 4 = 0 + 4$

$h = 0 + 4$

$h = 4$ ---- <em>First value of h</em>

$2h + 11 = 0$

Subtract 11 from both sides

$2h + 11 - 11 = 0 - 11$

$2h = 0 - 11$

$2h = -11$

Divide both sides by 2

$\frac{2h}{2} = -\frac{11}{2}$

$h = -\frac{11}{2}$ <em> ------ Second value of h</em>

Since height can be negative, we'll discard $h = -\frac{11}{2}$

Hence, the usable value of height is $h = 4$

Recall that $b = 3 + 2h$

Substitute 4 for h

$b = 3 + 2(4)$

$b = 3 + 8$

$b = 11$

Hence, the length of the base is 11 meters

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Answer:

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